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Invers dari matriks  adalah ....

Pertanyaan

Invers dari matriks begin mathsize 14px style straight B equals open parentheses table row 2 0 row 0 cell negative 1 end cell end table close parentheses end style adalah ....

  1. begin mathsize 14px style open parentheses table row cell 1 half end cell 0 row 0 cell negative 1 end cell end table close parentheses end style 

  2. begin mathsize 14px style open parentheses table row cell negative 1 end cell 0 row 0 cell 1 half end cell end table close parentheses end style 

  3. begin mathsize 14px style open parentheses table row 0 cell negative 1 half end cell row 1 0 end table close parentheses end style 

  4. begin mathsize 14px style open parentheses table row 0 cell negative 1 end cell row cell negative 1 half end cell 0 end table close parentheses end style 

  5. begin mathsize 14px style open parentheses table row cell 1 half end cell cell negative 1 half end cell row 1 cell negative 1 end cell end table close parentheses end style 

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Jawaban

jawabannya adalah A.

Pembahasan

Pertama, ingat bahwa 

begin mathsize 14px style straight B cross times straight B to the power of negative 1 end exponent equals straight I end style 

Misalkan 

begin mathsize 14px style straight B to the power of negative 1 end exponent equals open parentheses table row straight a straight b row straight c straight d end table close parentheses end style 

Maka,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row 2 0 row 0 cell negative 1 end cell end table close parentheses cross times open parentheses table row straight a straight b row straight c straight d end table close parentheses end cell equals cell open parentheses table row 1 0 row 0 1 end table close parentheses end cell row cell open parentheses table row cell 2 straight a end cell cell 2 straight b end cell row cell negative straight c end cell cell negative straight d end cell end table close parentheses end cell equals cell open parentheses table row 1 0 row 0 1 end table close parentheses end cell row blank blank blank end table end style 

Sehingga kita peroleh

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 straight a end cell equals cell 1 rightwards arrow straight a equals 1 half end cell row cell 2 straight b end cell equals cell 0 rightwards arrow straight b equals 0 end cell row cell negative straight c end cell equals cell 0 rightwards arrow straight c equals 0 end cell row cell negative straight d end cell equals cell 1 rightwards arrow straight d equals negative 1 end cell row blank blank blank end table end style 

Maka, didapat

begin mathsize 14px style straight A to the power of negative 1 end exponent equals open parentheses table row cell 1 half end cell 0 row 0 cell negative 1 end cell end table close parentheses end style 

Jadi, jawabannya adalah A.

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