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Pertanyaan

Hitunglah pH larutan:

N H subscript 4 Cl space 1 space M space left parenthesis K subscript italic b space N H subscript 4 O H equals 1 cross times 10 to the power of negative sign 5 end exponent right parenthesis

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Jawaban

pH dari N H subscript bold 4 Cl bold space bold 1 bold space italic M bold space bold left parenthesis K subscript italic b bold space N H subscript bold 4 O H bold equals bold 1 bold cross times bold 10 to the power of bold minus sign bold 5 end exponent bold right parenthesis adalah 4,5.

Pembahasan

N H subscript 4 Cl merupakan senyawa garam terhidrolisis sebagian yang bersifat asam.Perhitungan nilai pH pada senyawa garam bersifat asam adalah:

open square brackets O H to the power of minus sign close square brackets equals square root of K subscript italic w over K subscript italic b open square brackets G close square brackets end root

Keterangan:

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript italic w italic space end subscript end cell equals cell tetapan space ionisasi space air space left parenthesis 10 to the power of negative sign 14 end exponent right parenthesis end cell row cell K subscript italic b space end cell equals cell tetapan space ionisasi space basa end cell row cell open square brackets G close square brackets end cell equals cell konsentrasi space ion space garam space yang space terhidrolisis end cell end table

Berdasarkan persamaan di atas, pH N H subscript 4 Cl space 1 space M space left parenthesis K subscript italic b space N H subscript 4 O H equals 1 cross times 10 to the power of negative sign 5 end exponent right parenthesis adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets space space space end cell equals cell square root of K subscript italic w over K subscript italic b open square brackets N H subscript 4 Cl close square brackets end root end cell row blank equals cell square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 1 cross times 10 to the power of negative sign 5 end exponent end fraction open parentheses 1 space M close parentheses end root end cell row blank equals cell square root of 10 to the power of negative sign 9 end exponent end root end cell row blank equals cell 10 to the power of negative sign 4 comma 5 end exponent end cell row blank blank blank row cell pH space space space space space space space space end cell equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row blank equals cell negative sign log space 10 to the power of negative sign 4 comma 5 end exponent end cell row blank equals cell 4 comma 5 end cell end table

.Jadi, pH dari N H subscript bold 4 Cl bold space bold 1 bold space italic M bold space bold left parenthesis K subscript italic b bold space N H subscript bold 4 O H bold equals bold 1 bold cross times bold 10 to the power of bold minus sign bold 5 end exponent bold right parenthesis adalah 4,5.

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Jika 10,7 g salmiak, NH4​Cl(Mr​=53.3) dilarutkan dalam air hingga volume 500 mL, pH larutan tersebut adalah .... (Kb​NH3​=10−5)

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