Iklan

Iklan

Pertanyaan

Hitunglah nilai limit di bawah! x → ∞ lim ​ 8 x 3 + x − 2 x 2 − 2 x − 5 ​

Hitunglah nilai limit di bawah!

 

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

nilai dari adalah 0.

nilai dari begin mathsize 14px style limit as x rightwards arrow infinity of space fraction numerator x squared minus 2 x minus 5 over denominator 8 x cubed plus x minus 2 end fraction end style adalah 0.

Iklan

Pembahasan

Pembahasan
lock

Ingat: . Jadi, nilai dari adalah 0.

Ingat: limit as x rightwards arrow infinity of k over x to the power of n equals k over infinity to the power of n equals 0.

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of space fraction numerator x squared minus 2 x minus 5 over denominator 8 x cubed plus x minus 2 end fraction end cell equals cell limit as x rightwards arrow infinity of space fraction numerator x squared minus 2 x minus 5 over denominator 8 x cubed plus x minus 2 end fraction cross times fraction numerator begin display style 1 over x cubed end style over denominator x cubed end fraction end cell row blank equals cell limit as x rightwards arrow infinity of space fraction numerator begin display style x squared over x cubed end style minus begin display style fraction numerator 2 x over denominator x cubed end fraction end style minus begin display style 5 over x cubed end style over denominator begin display style fraction numerator 8 x cubed over denominator x cubed end fraction end style plus begin display style x over x cubed end style minus begin display style 2 over x cubed end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of space fraction numerator begin display style 1 over x minus 2 over x squared minus 5 over x cubed end style over denominator begin display style 8 plus 1 over x squared minus 2 over x cubed end style end fraction end cell row blank equals cell fraction numerator begin display style 1 over infinity minus 2 over infinity squared minus 5 over infinity cubed end style over denominator begin display style 8 plus 1 over infinity squared minus 2 over infinity cubed end style end fraction end cell row blank equals cell fraction numerator begin display style 0 minus 0 minus 0 end style over denominator begin display style 8 plus 0 minus 0 end style end fraction end cell row blank equals cell 0 over 8 end cell row blank equals 0 end table 

 Jadi, nilai dari begin mathsize 14px style limit as x rightwards arrow infinity of space fraction numerator x squared minus 2 x minus 5 over denominator 8 x cubed plus x minus 2 end fraction end style adalah 0.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4

New Maimuna

Mudah dimengerti

Iklan

Iklan

Pertanyaan serupa

x → ∞ lim ​ 2 x + 3 ​ − x − 2 ​ 2 x − 1 ​ + x + 1 ​ ​ = …

2

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia