Iklan

Pertanyaan

Hitunglah nilai dari x → 1 lim ​ x 3 + 5 x 2 + 2 x − 12 x 3 + 27 ​ .

Hitunglah nilai dari 

  1. undefined 

  2. undefined 

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

02

:

21

:

33

:

42

Klaim

Iklan

J. Joko

Master Teacher

Jawaban terverifikasi

Jawaban

, .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 1 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x cubed plus 27 over denominator x cubed plus 5 x squared plus 2 x minus 12 end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 7 end table end style.

Pembahasan

Pembahasan
lock

Jadi , .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 1 of fraction numerator x cubed plus 27 over denominator x cubed plus 5 x squared plus 2 x minus 12 end fraction end cell row blank equals cell fraction numerator limit as x rightwards arrow 1 of open parentheses x cubed plus 27 close parentheses over denominator limit as x rightwards arrow 1 of open parentheses x cubed plus 5 x squared plus 2 x minus 12 close parentheses end fraction end cell row blank equals cell fraction numerator limit as x rightwards arrow 1 of x cubed plus limit as x rightwards arrow 1 of 27 over denominator limit as x rightwards arrow 1 of x cubed plus 5 limit as x rightwards arrow 1 of x squared plus 2 limit as x rightwards arrow 1 of x minus limit as x rightwards arrow 1 of 12 end fraction end cell row blank equals cell fraction numerator 1 cubed plus 27 over denominator 1 cubed plus 5 times 1 squared plus 2 times 1 minus 12 end fraction end cell row blank equals cell fraction numerator 28 over denominator 1 plus 5 plus 2 minus 12 end fraction end cell row blank equals cell fraction numerator 28 over denominator negative 4 end fraction end cell row blank equals cell negative 7 end cell end table end style  

Jadibegin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 1 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator x cubed plus 27 over denominator x cubed plus 5 x squared plus 2 x minus 12 end fraction end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 7 end table end style.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Tentukan limit fungsi dari: x → 0 lim ​ x − 2 4 x 2 + 1 ​ = ....

43

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia