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Hitunglah [H+] campuran pada: 200 mL H2​SO4​(aq) 0,01 M dicampurkan dengan 300 mL CH3​COOH(aq) 0,4 M (Ka​=10−5)

Pertanyaan

Hitunglah begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style campuran pada:

200 mL begin mathsize 14px style H subscript 2 S O subscript 4 left parenthesis italic a italic q right parenthesis end style 0,01 M dicampurkan dengan 300 mL begin mathsize 14px style C H subscript 3 C O O H open parentheses italic a italic q close parentheses end style 0,4 M begin mathsize 14px style open parentheses K subscript a equals 10 to the power of negative sign 5 end exponent close parentheses end style space

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

 bold open square brackets H to the power of bold plus sign bold close square brackets campuran tersebut adalah bold 9 bold comma bold 2 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent bold space italic M.space

Pembahasan

Konsentrasi begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style pada campuran larutan ditentukan berdasarkan total jumlah mol ion H to the power of plus sign dalam campuran dan volume total campuran larutan tersebut. Langkah pengerjaan untuk menentukan begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style dalam campuran larutan asam sebagai berikut:

1. Menghitung mol ion H to the power of plus sign pada begin mathsize 14px style H subscript 2 S O subscript 4 end style:

 begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals 2 cross times open square brackets H subscript 2 S O subscript 4 close square brackets open square brackets H to the power of plus sign close square brackets equals 2 cross times 0 comma 01 open square brackets H to the power of plus sign close square brackets equals 0 comma 02 space M mol space H to the power of plus sign double bond open square brackets H to the power of plus sign close square brackets cross times V mol space H to the power of plus sign equals 0 comma 02 space M cross times 0 comma 2 space L mol space H equals 4 cross times 10 to the power of negative sign 3 end exponent space mol end style


2. Menghitung mol ion H to the power of plus sign pada begin mathsize 14px style C H subscript 3 C O O H end style:

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals square root of K subscript a cross times open square brackets C H subscript 3 C O O H close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of 10 to the power of negative sign 5 end exponent cross times 0 comma 4 end root open square brackets H to the power of plus sign close square brackets equals square root of 4 cross times 10 to the power of negative sign 6 end exponent end root open square brackets H to the power of plus sign close square brackets equals 2 cross times 10 to the power of negative sign 3 end exponent mol space H to the power of plus sign double bond open square brackets H to the power of plus sign close square brackets cross times V mol space H to the power of plus sign equals 2 cross times 10 to the power of negative sign 3 space end exponent M cross times 0 comma 3 space L mol space H to the power of plus sign equals 6 cross times 10 to the power of negative sign 4 end exponent space mol end style


3. Menghitung konsentrasi ion H to the power of plus sign dalam campuran

 begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals fraction numerator mol space total over denominator V space total end fraction open square brackets H to the power of plus sign close square brackets equals fraction numerator left parenthesis 4 cross times 10 to the power of negative sign 3 end exponent right parenthesis plus left parenthesis 6 cross times 10 to the power of negative sign 4 end exponent right parenthesis over denominator left parenthesis 0 comma 2 plus 0 comma 3 right parenthesis end fraction open square brackets H to the power of plus sign close square brackets equals fraction numerator 4 comma 6 cross times 10 to the power of negative sign 3 end exponent over denominator 0 comma 5 end fraction open square brackets H to the power of plus sign close square brackets equals 9 comma 2 cross times 10 to the power of negative sign 3 end exponent space M end style


Jadi, bold open square brackets H to the power of bold plus sign bold close square brackets campuran tersebut adalah bold 9 bold comma bold 2 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent bold space italic M.space

148

3.0 (1 rating)

Pertanyaan serupa

Hitunglah pH dari 1. CH3​COOH 0,1 M (Ka​=10−5)2. 100 mL HBr 0,2 M

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5.0

Jawaban terverifikasi

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