Hitunglah campuran pada: 200 mL 0,01 M dicampurkan dengan 300 mL 0,4 M

Hitunglah $begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style$ campuran pada:

200 mL $begin mathsize 14px style H subscript 2 S O subscript 4 left parenthesis italic a italic q right parenthesis end style$ 0,01 M dicampurkan dengan 300 mL $begin mathsize 14px style C H subscript 3 C O O H open parentheses italic a italic q close parentheses end style$ 0,4 M $begin mathsize 14px style open parentheses K subscript a equals 10 to the power of negative sign 5 end exponent close parentheses end style$ $space$

Jawaban:

Menghitung mol ion hidrogen pada $begin mathsize 14px style H subscript 2 S O subscript 4 end style$ :

$begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals 2 cross times open square brackets H subscript 2 S O subscript 4 close square brackets open square brackets H to the power of plus sign close square brackets equals 2 cross times 0 comma 01 open square brackets H to the power of plus sign close square brackets equals 0 comma 02 space M mol space H to the power of plus sign double bond open square brackets H to the power of plus sign close square brackets cross times V mol space H to the power of plus sign equals 0 comma 02 space M cross times 0 comma 2 space L mol space H equals 4 cross times 10 to the power of negative sign 3 end exponent space mol end style$

Menghitung mol ion hidrogen pada $begin mathsize 14px style C H subscript 3 C O O H end style$ :

$begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals square root of K subscript a cross times open square brackets C H subscript 3 C O O H close square brackets end root open square brackets H to the power of plus sign close square brackets equals square root of 10 to the power of negative sign 5 end exponent cross times 0 comma 4 end root open square brackets H to the power of plus sign close square brackets equals square root of 4 cross times 10 to the power of negative sign 6 end exponent end root open square brackets H to the power of plus sign close square brackets equals 2 cross times 10 to the power of negative sign 3 end exponent mol space H to the power of plus sign double bond open square brackets H to the power of plus sign close square brackets cross times V mol space H to the power of plus sign equals 2 cross times 10 to the power of negative sign 3 space end exponent M cross times 0 comma 3 space L mol space H to the power of plus sign equals 6 cross times 10 to the power of negative sign 4 end exponent space mol end style$

Menghitung konsentrasi ion hidrogen dalam campuran

$begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals fraction numerator mol space total over denominator V space total end fraction open square brackets H to the power of plus sign close square brackets equals fraction numerator left parenthesis 4 cross times 10 to the power of negative sign 3 end exponent right parenthesis plus left parenthesis 6 cross times 10 to the power of negative sign 4 end exponent right parenthesis over denominator left parenthesis 0 comma 2 plus 0 comma 3 right parenthesis end fraction open square brackets H to the power of plus sign close square brackets equals fraction numerator 4 comma 6 cross times 10 to the power of negative sign 3 end exponent over denominator 0 comma 5 end fraction open square brackets H to the power of plus sign close square brackets equals 9 comma 2 cross times 10 to the power of negative sign 3 end exponent space M end style$

$begin mathsize 14px style bold Jadi bold comma bold space begin bold style open square brackets H to the power of plus sign close square brackets end style bold space bold campuran bold space bold adalah bold space bold 9 bold comma bold 2 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent bold space italic M end style$ $space$

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