Hitung energi kinetik proton yang momentumnya 1,5 X 10-17 kg m/s! Massa proton 1,67 X 10-21 kg.

Pertanyaan

Hitung energi kinetik proton yang momentumnya 1,5 X 10-17 kg m/s! Massa proton 1,67 X 10-21 kg.undefined 

Y. Maghfirah

Master Teacher

Jawaban terverifikasi

Jawaban

energi kinetik proton adalah 28,53x10-11 J

Pembahasan

Diketahui:

p equals 1 comma 5 cross times 10 to the power of negative 17 end exponent space kgm divided by straight s m equals 1 comma 67 cross times 10 to the power of negative 21 end exponent space kg

Ditanya: EK

Penyelesaian:

Dari persamaan momentum relativistik tentukan kecepatan elektron terlebih dahulu:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row p equals cell m v end cell row cell 1 comma 5 cross times 10 to the power of negative 17 end exponent end cell equals cell fraction numerator 1 comma 67 cross times 10 to the power of negative 27 end exponent v over denominator square root of 1 minus begin display style v squared over c squared end style end root end fraction end cell row cell fraction numerator 1 comma 5 cross times 10 to the power of negative 17 end exponent over denominator 1 comma 67 cross times 10 to the power of negative 27 end exponent end fraction end cell equals cell fraction numerator v over denominator square root of 1 minus v squared over c squared end root end fraction end cell row cell open parentheses 0 comma 898 cross times 10 to the power of 10 close parentheses squared end cell equals cell open parentheses fraction numerator v over denominator square root of 1 minus v squared over c squared end root end fraction close parentheses squared space end cell row cell 0 comma 806 cross times 10 to the power of 20 end cell equals cell fraction numerator v squared over denominator 1 minus v squared over c squared end fraction end cell row cell 0 comma 806 cross times 10 to the power of 20 minus 0 comma 806 cross times 10 to the power of 20 v squared over c squared end cell equals cell v squared end cell row blank blank blank row cell 0 comma 806 cross times 10 to the power of 20 end cell equals cell v squared plus fraction numerator 0 comma 806 cross times 10 to the power of 20 v squared over denominator left parenthesis 3 cross times 10 to the power of 8 right parenthesis squared end fraction end cell row cell 0 comma 806 cross times 10 to the power of 20 end cell equals cell 896 comma 5 v squared end cell row cell v squared end cell equals cell fraction numerator 0 comma 806 cross times 10 to the power of 16 over denominator 896 comma 5 end fraction end cell row cell v squared end cell equals cell 8 comma 99 cross times 10 to the power of 16 end cell row v equals cell 2 comma 998 cross times 10 to the power of 8 space straight m divided by straight s end cell row v equals cell fraction numerator 2 comma 998 cross times 10 to the power of 8 over denominator 3 cross times 10 to the power of 8 end fraction end cell row v equals cell 0 comma 9994 c end cell end table end style   

Sehingga dari persamaan energi relativistik diperoleh:

Error converting from MathML to accessible text. 

Jadi, energi kinetik proton adalah 28,53x10-11 J

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