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Himpunan penyelesaian pertidaksamaan 2 lo g ( x + 2 ) + 2 lo g ( x − 2 ) ≤ 2 lo g 5 adalah...

Himpunan penyelesaian pertidaksamaan  adalah...

  1. open curly brackets right enclose x x greater or equal than negative 2 close curly brackets

  2. open curly brackets right enclose x x greater or equal than 2 close curly brackets

  3. open curly brackets right enclose x x greater or equal than 3 close curly brackets

  4. open curly brackets right enclose x 2 less than x less or equal than 3 close curly brackets

  5. open curly brackets right enclose x minus 2 less than x less than 2 close curly brackets

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

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Pembahasan

dengan syarat : x > -2 dan x > 2, maka Sehingga, irisan area dari gambar di atas adalah HP =

log presuperscript 2 space left parenthesis x plus 2 right parenthesis plus log presuperscript 2 space left parenthesis x minus 2 right parenthesis less or equal than log presuperscript 2 space 5  S y a r a t space left parenthesis x plus 2 right parenthesis greater than 0 rightwards arrow space x greater than negative 2  space space space space space space space space space space space space space left parenthesis x minus 2 right parenthesis greater than 0 rightwards arrow space x greater than 2  log presuperscript 2 space left parenthesis x plus 2 right parenthesis plus log presuperscript 2 space left parenthesis x minus 2 right parenthesis less or equal than log presuperscript 2 space 5  log presuperscript 2 space left parenthesis x plus 2 right parenthesis left parenthesis x minus 2 right parenthesis less or equal than log presuperscript 2 space 5  log presuperscript 2 space left parenthesis x squared minus 4 right parenthesis less or equal than log presuperscript 2 space 5  x squared minus 4 less or equal than 5  x squared minus 9 less or equal than 0  left parenthesis x plus 3 right parenthesis left parenthesis x minus 3 right parenthesis less or equal than 0  x equals negative 3 space a t a u space x equals 3 space  U j i space t i t i k space u n t u k space x equals 1 comma m a k a space 1 squared minus 9 equals negative 8 less than 0  K a r e n a space minus 3 less than 1 less than 3 comma space m a k a space u n t u k space d a e r a h space minus 3 less than x less than 3 space b e r n i l a i space n e g a t i f  A m b i l space y a n g space n e g a t i f comma space m a k a space d i d a p a t space p e n y e l e s a i a n

dengan syarat : x > -2 dan x > 2, maka 

Sehingga, irisan area dari gambar di atas adalah

HP = open curly brackets right enclose x 2 less than x less or equal than 3 close curly brackets

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