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Hasil kali kelarutan  dalam air pada suhu tertentu adalah . Tentukan kelarutan  dalam: Larutan NaOH 0,1 M

Pertanyaan

Hasil kali kelarutan Mg open parentheses O H close parentheses subscript 2 dalam air pada suhu tertentu adalah 2 cross times 10 to the power of negative sign 11 end exponent. Tentukan kelarutan Mg open parentheses O H close parentheses subscript 2 dalam:

Larutan NaOH 0,1 M

Pembahasan Soal:

Penentuan kelarutan Mg open parentheses O H close parentheses subscript 2 dalam larutan NaOH 0,1 M dapat dihitung berdasarkan pengaruh ion senama, dimana kedua zat memiliki ion senama yaitu O H to the power of minus sign.

table attributes columnalign right center left columnspacing 0px end attributes row cell Na O H end cell rightwards arrow cell Na to the power of plus sign and O H to the power of minus sign end cell row blank blank cell 10 to the power of negative sign 1 end exponent space M space space space space space space space space space space space 10 to the power of negative sign 1 end exponent space M end cell row blank blank blank row cell Mg open parentheses O H close parentheses subscript 2 end cell rightwards harpoon over leftwards harpoon cell Mg to the power of 2 plus sign and 2 O H to the power of minus sign end cell row blank blank cell space space space space s space space space space space space space space space space space space space space s space space space space space space space space space 2 s end cell row blank blank blank row cell K subscript sp end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell 2 cross times 10 to the power of negative sign 11 end exponent end cell equals cell s cross times open parentheses 10 to the power of negative sign 1 end exponent close parentheses squared end cell row cell 2 cross times 10 to the power of negative sign 11 end exponent end cell equals cell s cross times 10 to the power of negative sign 2 end exponent end cell row s equals cell fraction numerator 2 cross times 10 to the power of negative sign 11 end exponent over denominator 10 to the power of negative sign 2 end exponent end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 9 end exponent end cell end table 

Jadi, kelarutan Mg open parentheses O H close parentheses subscript 2 dalam larutan NaOH 0,1 M adalah Error converting from MathML to accessible text..

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 06 Mei 2021

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