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Hasil dari −32​⎝⎛​3−36​129−21​1500​⎠⎞​=...

Pertanyaan

Hasil dari begin mathsize 14px style negative 2 over 3 open parentheses table row 3 12 15 row cell negative 3 end cell 9 0 row 6 cell negative 21 end cell 0 end table close parentheses equals... end style 

  1. begin mathsize 14px style open parentheses table row cell negative 2 end cell cell negative 8 end cell cell negative 10 end cell row 2 cell negative 6 end cell 0 row cell negative 4 end cell 14 0 end table close parentheses end style 

  2. begin mathsize 14px style open parentheses table row 2 8 10 row cell negative 2 end cell 6 0 row 4 cell negative 14 end cell 0 end table close parentheses end style 

  3. begin mathsize 14px style open parentheses table row cell negative 2 end cell 8 cell negative 10 end cell row 2 6 cell negative 2 over 3 end cell row cell negative 4 end cell cell negative 14 end cell cell negative 2 over 3 end cell end table close parentheses end style 

  4. begin mathsize 14px style open parentheses table row 2 cell negative 8 end cell 10 row cell negative 2 end cell cell negative 6 end cell cell 2 over 3 end cell row 4 14 cell 2 over 3 end cell end table close parentheses end style 

  5. begin mathsize 14px style open parentheses table row cell negative 1 end cell cell negative 4 end cell cell negative 5 end cell row cell negative 1 end cell 3 0 row 2 cell negative 7 end cell 0 end table close parentheses end style 

M. Robo

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Perkalian skalar pada matriks berarti setiap elemen pada matriks dikali dengan skalar tersebut sehingga

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px minus size 14px 2 over size 14px 3 open parentheses table row size 14px 3 size 14px 12 size 14px 15 row cell size 14px minus size 14px 3 end cell size 14px 9 size 14px 0 row size 14px 6 cell size 14px minus size 14px 21 end cell size 14px 0 end table close parentheses end cell size 14px equals cell open parentheses table row cell size 14px 3 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell cell size 14px 12 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell cell size 14px 15 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell row cell open parentheses size 14px minus size 14px 3 close parentheses size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell cell size 14px 9 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell cell size 14px 0 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell row cell size 14px 6 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell cell open parentheses size 14px minus size 14px 21 close parentheses size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell cell size 14px 0 size 14px times open parentheses size 14px minus size 14px 2 over size 14px 3 close parentheses end cell end table close parentheses end cell row blank size 14px equals cell open parentheses table attributes columnalign center center center end attributes row cell size 14px minus size 14px 2 end cell cell size 14px minus size 14px 8 end cell cell size 14px minus size 14px 10 end cell row size 14px 2 cell size 14px minus size 14px 6 end cell size 14px 0 row cell size 14px minus size 14px 4 end cell size 14px 14 size 14px 0 end table close parentheses end cell end table    

Jadi, jawaban yang tepat adalah A.

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Diketahui P=(−x−9​2−2​), Q=(2y7​−53x​) dan R=(107​2−y​) . Jika 3P+2Q−R=(−16−20​−6−3​) , maka nilai 3x - 2y =  ....

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