Iklan

Pertanyaan

Hasil dari

Hasil dari fraction numerator sin invisible function application open parentheses fraction numerator 5 pi over denominator 9 end fraction minus pi over 18 close parentheses over denominator cos invisible function application open parentheses pi over 3 plus pi over 12 close parentheses end fraction equals

  1. 1 half square root of 2

  2. 1 half square root of 3 space

  3. 1

  4. 1 third square root of 3

  5. square root of 6 plus square root of 2

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

16

:

50

:

25

Klaim

Iklan

N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Pembahasan

fraction numerator sin invisible function application open parentheses fraction numerator 5 pi over denominator 9 end fraction minus pi over 18 close parentheses over denominator cos invisible function application open parentheses pi over 3 plus pi over 12 close parentheses end fraction equals fraction numerator sin invisible function application open parentheses fraction numerator 10 pi minus pi over denominator 18 end fraction close parentheses over denominator cos invisible function application open parentheses fraction numerator 4 pi plus pi over denominator 12 end fraction close parentheses end fraction  rightwards double arrow fraction numerator sin invisible function application open parentheses fraction numerator 9 pi over denominator 18 end fraction close parentheses over denominator cos invisible function application open parentheses fraction numerator 5 pi over denominator 12 end fraction close parentheses end fraction  rightwards double arrow fraction numerator sin invisible function application pi over 2 over denominator cos invisible function application fraction numerator 5 pi over denominator 12 end fraction end fraction  rightwards double arrow fraction numerator sin invisible function application 90 degree over denominator cos invisible function application 75 degree end fraction  rightwards double arrow fraction numerator 1 over denominator cos invisible function application open parentheses 45 degree plus 30 degree close parentheses end fraction equals fraction numerator 1 over denominator cos invisible function application 45 degree cos invisible function application 30 degree minus sin invisible function application 45 degree sin invisible function application 30 degree end fraction  rightwards double arrow fraction numerator 1 over denominator 1 half square root of 2 open parentheses 1 half square root of 3 close parentheses minus 1 half square root of 2 open parentheses 1 half close parentheses end fraction equals fraction numerator 1 over denominator 1 fourth square root of 6 minus 1 fourth square root of 2 end fraction  rightwards double arrow fraction numerator 4 over denominator square root of 6 minus square root of 2 end fraction  rightwards double arrow fraction numerator 4 over denominator square root of 6 minus square root of 2 end fraction cross times fraction numerator square root of 6 plus square root of 2 over denominator square root of 6 plus square root of 2 end fraction  rightwards double arrow square root of 6 plus square root of 2

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Diketahui A + B = 3 π ​ dan sin A ⋅ sin B = 4 1 ​ . Nilai dari ekspresi cos ( A − B ) = . . . .

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia