Hasil dari 2​(48​+34​−8​) adalah ....

Pertanyaan

Hasil dari begin mathsize 14px style square root of 2 open parentheses fourth root of 8 plus cube root of 4 minus square root of 8 close parentheses end style adalah ....

  1. begin mathsize 14px style 2 plus cube root of 2 squared end root minus fifth root of 2 cubed end root end style 

  2. begin mathsize 14px style fourth root of 2 to the power of 5 end root plus root index 6 of 2 to the power of 7 end root minus 4 end style 

  3. begin mathsize 14px style cube root of 2 squared end root plus fifth root of 2 cubed end root minus 4 end style 

  4. begin mathsize 14px style fifth root of 2 to the power of 4 end root plus root index 7 of 2 to the power of 6 end root minus square root of 2 cubed end root end style 

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Perhatikan bahwa

begin mathsize 14px style square root of 2 open parentheses fourth root of 8 plus cube root of 4 minus square root of 8 close parentheses equals square root of 2 cross times fourth root of 8 plus square root of 2 cross times cube root of 4 minus square root of 2 cross times square root of 8 equals 2 to the power of 1 half end exponent cross times 8 to the power of 1 fourth end exponent plus 2 to the power of 1 half end exponent cross times 4 to the power of 1 third end exponent minus 2 to the power of 1 half end exponent cross times 8 to the power of 1 half end exponent equals 2 to the power of 1 half end exponent cross times open parentheses 2 cubed close parentheses to the power of 1 fourth end exponent plus 2 to the power of 1 half end exponent cross times open parentheses 2 squared close parentheses to the power of 1 third end exponent minus 2 to the power of 1 half end exponent cross times open parentheses 2 cubed close parentheses to the power of 1 half end exponent equals 2 to the power of 1 half end exponent cross times 2 to the power of 3 over 4 end exponent plus 2 to the power of 1 half end exponent cross times 2 to the power of 2 over 3 end exponent minus 2 to the power of 1 half end exponent cross times 2 to the power of 3 over 2 end exponent equals 2 to the power of 1 half plus 3 over 4 end exponent plus 2 to the power of 1 half plus 2 over 3 end exponent minus 2 to the power of 1 half plus 3 over 2 end exponent equals 2 to the power of 5 over 4 end exponent plus 2 to the power of 7 over 6 end exponent minus 2 squared equals fourth root of 2 to the power of 5 end root plus root index 6 of 2 to the power of 7 end root minus 4 end style  

Dengan demikian, hasil dari undefined adalah undefined.

Jadi, jawaban yang tepat adalah B.

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Jika b=a3 dan c=a23​, maka hasil dari 45a6​+20b2​−5c4​ adalah ....

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