Roboguru
SD

Hasil dari (−2)2×(22​)−2+(−2)0 adalah ...

Pertanyaan

Hasil dari begin mathsize 14px style left parenthesis negative 2 right parenthesis squared cross times open parentheses 2 square root of 2 end root close parentheses to the power of negative 2 end exponent plus open parentheses negative 2 close parentheses to the power of 0 end style adalah ...

S. Dwi

Master Teacher

Jawaban terverifikasi

Jawaban

 hasil dari begin mathsize 14px style left parenthesis negative 2 right parenthesis squared cross times open parentheses 2 square root of 2 end root close parentheses to the power of negative 2 end exponent plus open parentheses negative 2 close parentheses to the power of 0 end style adalah 1 1 half.

Pembahasan

Ingat kembali sifat bilangan berpangkat berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell a to the power of negative m end exponent end cell equals cell 1 over a to the power of m end cell row cell a to the power of 0 end cell equals 1 row cell open parentheses a times b close parentheses to the power of m end cell equals cell a to the power of m times b to the power of m end cell end table

sehingga didapat

table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis negative 2 right parenthesis squared cross times open parentheses 2 square root of 2 close parentheses to the power of negative 2 end exponent plus open parentheses negative 2 close parentheses to the power of 0 end cell equals cell left parenthesis negative 2 right parenthesis squared cross times 1 over open parentheses 2 times 2 to the power of begin display style 1 half end style end exponent close parentheses squared plus open parentheses negative 2 close parentheses to the power of 0 end cell row blank equals cell fraction numerator open parentheses negative 2 close parentheses squared over denominator 2 squared times 2 to the power of begin display style 1 half end style times 2 end exponent end fraction plus 1 end cell row blank equals cell fraction numerator 4 over denominator 2 squared times 2 end fraction plus 1 end cell row blank equals cell fraction numerator up diagonal strike 4 over denominator up diagonal strike 4 times 2 end fraction plus 1 end cell row blank equals cell 1 half plus 1 end cell row blank equals cell 1 1 half end cell end table 

Jadi, hasil dari begin mathsize 14px style left parenthesis negative 2 right parenthesis squared cross times open parentheses 2 square root of 2 end root close parentheses to the power of negative 2 end exponent plus open parentheses negative 2 close parentheses to the power of 0 end style adalah 1 1 half.

78

0.0 (0 rating)

Pertanyaan serupa

Tentukan hasil operasi bilangan berikut dalam bentuk akar! c. (p43​q−31​r​)4

27

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia