Roboguru
SD

Hasil dari ∫x23x4−2x3+4x2+1​ dx adalah...

Pertanyaan

Hasil dari begin mathsize 14px style integral fraction numerator 3 x to the power of 4 minus 2 x cubed plus 4 x squared plus 1 over denominator x squared end fraction space dx end style adalah... 

  1. size 14px 3 size 14px x to the power of size 14px 3 size 14px minus size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 4 size 14px x size 14px minus size 14px 1 over size 14px x size 14px plus size 14px C   

  2. size 14px x to the power of size 14px 3 size 14px minus size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 4 size 14px x size 14px plus size 14px 1 over size 14px x size 14px plus size 14px C   

  3. size 14px x to the power of size 14px 3 size 14px minus size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 4 size 14px x size 14px minus size 14px 1 over size 14px x size 14px plus size 14px C         

  4. size 14px x to the power of size 14px 3 size 14px minus size 14px x to the power of size 14px 2 size 14px plus size 14px 4 size 14px x size 14px minus size 14px 1 over size 14px x size 14px plus size 14px C  

  5. size 14px x to the power of size 14px 3 size 14px minus size 14px x to the power of size 14px 2 size 14px plus size 14px 4 size 14px x size 14px plus size 14px 1 over size 14px x size 14px plus size 14px C  

I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D

Pembahasan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript blank superscript blank open parentheses fraction numerator 3 x to the power of 4 minus 2 x cubed plus 4 x squared plus 1 over denominator x squared end fraction close parentheses d x end cell equals cell integral open parentheses x to the power of negative 2 end exponent open parentheses 3 x to the power of 4 minus 2 x cubed plus 4 x squared plus 1 close parentheses close parentheses d x end cell row blank equals cell integral open parentheses 3 x squared minus 2 x plus 4 plus x to the power of negative 2 end exponent close parentheses d x end cell row blank equals cell fraction numerator 3 x cubed over denominator 3 end fraction minus fraction numerator 2 x squared over denominator 2 end fraction plus 4 x plus fraction numerator x to the power of negative 1 end exponent over denominator negative 1 end fraction plus C end cell row blank equals cell x cubed minus x squared plus 4 x minus 1 over x plus C end cell end table end style 

Jadi, jawaban yang tepat adalah D

251

4.9 (15 rating)

Siti Saputri278

Makasih ❤️

Aliah

Bantu banget

Pertanyaan serupa

y=∫3dx

13

4.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia