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Pertanyaan

From the plat of A triangular tract of land, A surveyor knows that the perimeter is 70 m. The lengths on the plat have been blurred, but the surveyor knows, that the length of the longest side is 10 m less than the sum of the other two sides, and the longest side is 2 m less than twice the shortest side. Find the length of the three sides of the triangular tract.

From the plat of A triangular tract of land, A surveyor knows that the perimeter is 70 m. The lengths on the plat have been blurred, but the surveyor knows, that the length of the longest side is 10 m less than the sum of the other two sides, and the longest side is 2 m less than twice the shortest side. Find the length of the three sides of the triangular tract.

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Jawaban

panjang ketiga sisi segitiga tersebut adalah , dan

panjang ketiga sisi segitiga tersebut adalah 16 space straight m, 24 space straight m dan 30 space straight m 

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Pembahasan

Diketahui plat berbentuk segitiga dengan sisi , dan .Model matematika dari persamasalahan tersebut adalah: Dibuat dalam bentuk matriks menjadi: Dengan aturan Cramer, maka: Sehingga: Didapat: Jadi, panjang ketiga sisi segitiga tersebut adalah , dan

Diketahui plat berbentuk segitiga dengan sisi a, b dan c. Model matematika dari persamasalahan tersebut adalah:

a plus b plus c equals 70 c equals left parenthesis a plus b right parenthesis minus 10 space rightwards double arrow space a plus b minus c equals 10 space c equals 2 a minus 2 space rightwards double arrow space 2 a minus c equals 2 

Dibuat dalam bentuk matriks menjadi:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open vertical bar table row 1 1 1 row 1 1 cell negative 1 end cell row 2 0 cell negative 1 end cell end table close vertical bar end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell table row 70 row 10 row 2 end table end cell end table 

Dengan aturan Cramer, maka:

table attributes columnalign right center left columnspacing 0px end attributes row D equals cell open vertical bar table row 1 1 1 row 1 1 cell negative 1 end cell row 2 0 cell negative 1 end cell end table close vertical bar table row 1 1 row 1 1 row 2 0 end table end cell row blank equals cell negative 1 plus left parenthesis negative 2 right parenthesis plus 0 minus 2 minus 0 minus left parenthesis negative 1 right parenthesis end cell row blank equals cell negative 4 end cell row blank blank blank row cell D subscript a end cell equals cell open vertical bar table row 70 1 1 row 10 1 cell negative 1 end cell row 2 0 cell negative 1 end cell end table close vertical bar table row 70 1 row 10 1 row 2 0 end table end cell row blank equals cell negative 70 plus left parenthesis negative 2 right parenthesis plus 0 minus 2 minus 0 minus left parenthesis negative 10 right parenthesis end cell row blank equals cell negative 64 end cell row blank blank blank row cell D subscript b end cell equals cell open vertical bar table row 1 70 1 row 1 10 cell negative 1 end cell row 2 2 cell negative 1 end cell end table close vertical bar table row 1 70 row 1 10 row 2 2 end table end cell row blank equals cell negative 10 plus left parenthesis negative 140 right parenthesis plus 2 minus 20 minus left parenthesis negative 2 right parenthesis minus left parenthesis negative 70 right parenthesis end cell row blank equals cell negative 96 end cell row blank blank blank row cell D subscript c end cell equals cell open vertical bar table row 1 1 70 row 1 1 10 row 2 0 2 end table close vertical bar table row 1 1 row 1 1 row 2 0 end table end cell row blank equals cell 2 plus 20 plus 0 minus 140 minus 0 minus 2 end cell row blank equals cell negative 120 end cell end table    

Sehingga:

table attributes columnalign right center left columnspacing 0px end attributes row a equals cell D subscript a over D end cell row blank equals cell fraction numerator negative 64 over denominator negative 4 end fraction end cell row blank equals 4 row blank blank blank row b equals cell D subscript b over D end cell row blank equals cell fraction numerator negative 96 over denominator negative 4 end fraction end cell row blank equals 24 row blank blank blank row c equals cell D subscript c over D end cell row blank equals cell fraction numerator negative 120 over denominator negative 4 end fraction end cell row blank equals 30 end table 

Didapat:

a equals 16 comma space b equals 24 space dan space c equals 30 

Jadi, panjang ketiga sisi segitiga tersebut adalah 16 space straight m, 24 space straight m dan 30 space straight m 

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