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Dua muatan q sebesar  dipegang tetap sehingga berjarak d = 20 cm satu sama lain seperti gambar. Berapakah potensial listrik di titik C?

Pertanyaan

Dua muatan q sebesar begin mathsize 14px style 2 comma 0 cross times 10 to the power of negative 6 end exponent space straight C end style dipegang tetap sehingga berjarak d = 20 cm satu sama lain seperti gambar. Berapakah potensial listrik di titik C?

  1. ...space

  2. ...undefined

Pembahasan Soal:

Diketahui:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell q subscript 1 end cell equals cell q subscript 2 equals 2 times 10 to the power of negative 6 end exponent space straight C end cell row d equals cell 20 space cm equals 0 comma 2 space straight m end cell end table end style 

Ditanyakan:

V = ? di titik C

Jawab:

Jarak antara begin mathsize 14px style q subscript 1 end style/begin mathsize 14px style q subscript 2 end style dan titik C:

begin mathsize 14px style r equals square root of open parentheses 1 half open parentheses 0 comma 2 close parentheses close parentheses squared plus open parentheses 1 half open parentheses 0 comma 2 close parentheses close parentheses squared end root equals 0 comma 1 square root of 2 space straight m end style  

Potensial listrik yang berasal dari banyak muatan pada suatu titik:

table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript C end cell equals cell sum k q subscript i over r subscript i equals k open parentheses q subscript 1 over r subscript 1 plus q subscript 2 over r subscript 2 close parentheses end cell row blank equals cell open parentheses 9 times 10 to the power of 9 close parentheses open parentheses fraction numerator 2 times 10 to the power of negative 6 end exponent over denominator 0 comma 1 square root of 2 end fraction plus fraction numerator 2 times 10 to the power of negative 6 end exponent over denominator 0 comma 1 square root of 2 end fraction close parentheses end cell row blank equals cell open parentheses 9 times 10 to the power of 9 close parentheses open parentheses fraction numerator 4 times 10 to the power of negative 6 end exponent over denominator 0 comma 1 square root of 2 end fraction close parentheses end cell row cell V subscript C end cell equals cell fraction numerator 36 over denominator square root of 2 end fraction times 10 to the power of 4 equals bold 2 bold comma bold 54 bold times bold 10 to the power of bold 5 bold space bold V end cell end table  

Dengan demikian, potensial listrik di titik C akibat muatan 1 dan 2 sebesar 2 comma 54 times 10 to the power of 5 space straight V (nilai mutlak).

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Juli 2021

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