Iklan

Iklan

Pertanyaan

Ditentukan fungsi-fungsi f , g , dan h sebagai berikut: f ( x ) = 3 x − 1 ; g ( x ) = x ​ ; dan h ( x ) = x 2 + 2 . Tentukan: c. ( f ∘ g ) ( 4 ) , ( f ∘ g ) ( 2 ) , ( f ∘ g ) ( − 2 ) , ( h ∘ g ) ( 3 ) , ( h ∘ g ) ( − 3 )

Ditentukan fungsi-fungsi  sebagai berikut: ; dan . Tentukan:

c.  

  1. ...space 

  2. ...

Iklan

D. Entry

Master Teacher

Jawaban terverifikasi

Jawaban

nilai .

nilai begin mathsize 14px style bottom enclose bold left parenthesis bold h bold ring operator bold g bold right parenthesis bold left parenthesis bold minus bold 3 bold right parenthesis bold equals bold minus bold 1 end enclose end style.

Iklan

Pembahasan

Pembahasan
lock

Jadi, nilai . Jadi, nilai . Jadi, nilai . Jadi, nilai . Jadi, nilai .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f ring operator g close parentheses open parentheses x close parentheses end cell equals cell 3 square root of x minus 1 end cell row cell open parentheses f ring operator g close parentheses open parentheses 4 close parentheses end cell equals cell 3 square root of 4 minus 1 end cell row blank equals cell 6 minus 1 end cell row blank equals 5 row blank blank blank end table end style 

Jadi, nilai begin mathsize 14px style bottom enclose begin bold style left parenthesis f ring operator g right parenthesis end style begin bold style left parenthesis 4 right parenthesis end style bold equals bold 5 end enclose end style.

begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses x close parentheses equals 3 square root of x minus 1 open parentheses f ring operator g close parentheses open parentheses 2 close parentheses equals 3 square root of 2 minus 1 end style 

Jadi, nilai begin mathsize 14px style bottom enclose begin bold style left parenthesis f ring operator g right parenthesis end style begin bold style left parenthesis 2 right parenthesis end style bold equals bold 3 square root of bold 2 bold minus bold 1 end enclose end style.

begin mathsize 14px style open parentheses f ring operator g close parentheses open parentheses x close parentheses equals 3 square root of x minus 1 open parentheses f ring operator g close parentheses open parentheses negative 2 close parentheses equals 3 square root of negative 2 end root minus 1 end style 

Jadi, nilai begin mathsize 14px style bottom enclose begin bold style left parenthesis f ring operator g right parenthesis end style begin bold style left parenthesis negative 2 right parenthesis end style bold equals bold 3 square root of bold minus bold 2 end root bold minus bold 1 end enclose end style.

begin mathsize 14px style open parentheses h ring operator g close parentheses open parentheses x close parentheses equals x plus 2 open parentheses h ring operator g close parentheses open parentheses 3 close parentheses equals 3 plus 2 equals 5 end style

Jadi, nilai begin mathsize 14px style bottom enclose begin bold style left parenthesis h ring operator g right parenthesis end style begin bold style left parenthesis 3 right parenthesis end style bold equals bold 5 end enclose end style.

begin mathsize 14px style open parentheses h ring operator g close parentheses open parentheses x close parentheses equals x plus 2 open parentheses h ring operator g close parentheses open parentheses negative 3 close parentheses equals negative 3 plus 2 equals negative 1 end style

Jadi, nilai begin mathsize 14px style bottom enclose bold left parenthesis bold h bold ring operator bold g bold right parenthesis bold left parenthesis bold minus bold 3 bold right parenthesis bold equals bold minus bold 1 end enclose end style.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Iklan

Pertanyaan serupa

Diketahui fungsi f ( x ) = 5 x + 3 dan .Hasil dari ( f ∘ g ) ( 0 ) adalah...

1

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia