Roboguru

Diketahui vektor  dan , tentukan vektor  sehingga persamaan berikut bernilai benar .

Pertanyaan

Diketahui vektor begin mathsize 14px style stack text p end text with rightwards arrow on top equals open parentheses table row 3 row 2 end table close parentheses comma space stack text q end text with rightwards arrow on top equals open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses end style dan undefined, tentukan vektor begin mathsize 14px style x with rightwards arrow on top end style sehingga persamaan berikut bernilai benar Error converting from MathML to accessible text..  

Pembahasan Video:

Pembahasan Soal:

Diketahui vektor begin mathsize 14px style stack text p end text with rightwards arrow on top equals open parentheses table row 3 row 2 end table close parentheses comma space stack text q end text with rightwards arrow on top equals open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses end style dan undefined, tentukan v

Vektor begin mathsize 14px style x with rightwards arrow on top end style sehingga Error converting from MathML to accessible text. bernilai benar, dapat di cari dengan melakukan substitusi vektor-vektor begin mathsize 14px style stack text p end text with rightwards arrow on top equals open parentheses table row 3 row 2 end table close parentheses comma space stack text q end text with rightwards arrow on top equals open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses end style dan undefined pada persamaan.

Misal: undefined, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell negative 4 open parentheses table row 3 row 2 end table close parentheses minus 2 open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses plus 3 open parentheses table row 0 row 6 end table close parentheses end cell row cell open parentheses table row cell negative 12 end cell row cell negative 8 end cell end table close parentheses minus 2 open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses plus open parentheses table row 0 row 18 end table close parentheses end cell row cell negative 2 open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 3 end cell row 17 end table close parentheses minus open parentheses table row cell negative 12 end cell row cell negative 8 end cell end table close parentheses end cell row cell negative 2 open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row 9 row 25 end table close parentheses end cell row cell open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell negative 1 half open parentheses table row 9 row 25 end table close parentheses end cell row cell open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 9 over 2 end cell row cell negative 25 over 2 end cell end table close parentheses end cell row blank rightwards arrow cell x with rightwards arrow on top equals open parentheses table row cell negative 4 comma 5 end cell row cell negative 12 comma 5 end cell end table close parentheses end cell row blank blank blank end table end style

Jadi, agar Error converting from MathML to accessible text. bernilai benar, maka begin mathsize 14px style x with rightwards arrow on top equals open parentheses table row cell negative 4 comma 5 end cell row cell negative 12 comma 5 end cell end table close parentheses end style.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

D. Entry

Terakhir diupdate 07 Juni 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Perhatikan gambar jajar genjang di samping dan tentukan : b) Koordinat titik S

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell stack P S with rightwards arrow on top end cell equals cell stack Q R with rightwards arrow on top end cell row cell s with rightwards arrow on top minus p with rightwards arrow on top end cell equals cell r with rightwards arrow on top minus q with rightwards arrow on top end cell row cell straight s with rightwards arrow on top minus open parentheses table row 3 row 0 end table close parentheses end cell equals cell open parentheses table row 9 row 7 end table close parentheses minus open parentheses table row 5 row 3 end table close parentheses end cell row cell s with rightwards arrow on top end cell equals cell open parentheses table row 9 row 7 end table close parentheses minus open parentheses table row 5 row 3 end table close parentheses plus open parentheses table row 3 row 0 end table close parentheses end cell row cell s with rightwards arrow on top end cell equals cell open parentheses table row 7 row 4 end table close parentheses end cell end table

Jadi, koordinat titik S (7, 4).

     

0

Roboguru

Jika vektor  dan , vektor  yang memenuhi operasi  adalah ...

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 3 v with rightwards arrow on top plus 2 w with rightwards arrow on top end cell equals cell u with rightwards arrow on top minus v with rightwards arrow on top end cell row cell 2 w with rightwards arrow on top end cell equals cell u with rightwards arrow on top minus 4 v with rightwards arrow on top end cell row cell 2 w with rightwards arrow on top end cell equals cell open parentheses table row 4 row 6 end table close parentheses minus 4 open parentheses table row 3 row cell negative 1 end cell end table close parentheses end cell row cell 2 w with rightwards arrow on top end cell equals cell open parentheses table row cell 4 minus 4 times 3 end cell row cell 6 minus 4 times open parentheses negative 1 close parentheses end cell end table close parentheses end cell row cell 2 w with rightwards arrow on top end cell equals cell open parentheses table row cell negative 8 end cell row 10 end table close parentheses end cell row cell w with rightwards arrow on top end cell equals cell 1 half open parentheses table row cell negative 8 end cell row 10 end table close parentheses end cell row cell w with rightwards arrow on top end cell equals cell open parentheses table row cell negative 4 end cell row 5 end table close parentheses end cell end table end style 

Jadi, jawaban yang tepat adalah C.

0

Roboguru

Diketahui vektor  dan , tentukan vektor  sehingga persamaan berikut bernilai benar .

Pembahasan Soal:

Vektor begin mathsize 14px style x with rightwards arrow on top end style sehingga size 14px p with size 14px rightwards arrow on top size 14px plus size 14px q with size 14px rightwards arrow on top size 14px plus size 14px x with size 14px rightwards arrow on top size 14px equals size 14px r with size 14px rightwards arrow on top bernilai benar, dapat dicari dengan melakukan substitusi vektor-vektor  begin mathsize 14px style stack text p end text with rightwards arrow on top equals open parentheses table row 3 row 2 end table close parentheses comma space stack text q end text with rightwards arrow on top equals open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses end style dan undefined pada persamaan.

Misal: undefined, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row 3 row 2 end table close parentheses plus open parentheses table row cell negative 3 end cell row cell negative 1 end cell end table close parentheses plus open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row 0 row 6 end table close parentheses end cell row cell open parentheses table row 0 row 1 end table close parentheses plus open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row 0 row 6 end table close parentheses end cell row cell open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row 0 row 6 end table close parentheses minus open parentheses table row 0 row 1 end table close parentheses end cell row cell open parentheses table row cell x subscript 1 end cell row cell x subscript 2 end cell end table close parentheses end cell equals cell open parentheses table row 0 row 5 end table close parentheses end cell row blank rightwards arrow cell x subscript 1 equals 0 logical and x subscript 2 equals 5 end cell end table end style

Jadi, persamaan berikut bernilai benar size 14px p with size 14px rightwards arrow on top size 14px plus size 14px q with size 14px rightwards arrow on top size 14px plus size 14px x with size 14px rightwards arrow on top size 14px equals size 14px r with size 14px rightwards arrow on top saat vektor begin mathsize 14px style x with rightwards arrow on top equals open parentheses table row 0 row 5 end table close parentheses end style.

0

Roboguru

Jika  dan  maka koordinat titik A adalah ....

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell AB with rightwards arrow on top end cell equals cell straight B with rightwards arrow on top minus straight A with rightwards arrow on top end cell row cell straight A with rightwards arrow on top end cell equals cell straight B with rightwards arrow on top minus AB with rightwards arrow on top end cell row cell straight A with rightwards arrow on top end cell equals cell open parentheses table row cell negative 1 end cell row 8 end table close parentheses minus open parentheses table row 3 row cell negative 4 end cell end table close parentheses end cell row cell straight A with rightwards arrow on top end cell equals cell open parentheses table row cell negative 4 end cell row 12 end table close parentheses end cell end table   

Jadi, Titik A adalah C. begin mathsize 14px style bold left parenthesis bold minus bold 4 bold comma blank bold 12 bold right parenthesis end style   
  

0

Roboguru

Diketahui vektor . Jika  dengan koordinat titik , koordinat titik B adalah....

Pembahasan Soal:

Diketahui vektor u with rightwards arrow on top equals open parentheses table row cell negative 3 end cell row 4 end table close parentheses space dan space straight v with rightwards arrow on top equals open parentheses table row 2 row 5 end table close parentheses, serta stack A B with rightwards arrow on top equals 3 u with rightwards arrow on top minus v with rightwards arrow on top dengan koordinat titik A left parenthesis 5 comma negative 3 right parenthesis, maka

table attributes columnalign right center left columnspacing 0px end attributes row cell stack A B with rightwards arrow on top end cell equals cell 3 u with rightwards arrow on top minus v with rightwards arrow on top end cell row cell open parentheses table row cell b subscript 1 minus a subscript 1 end cell row cell b subscript 2 minus a subscript 2 end cell end table close parentheses end cell equals cell 3 open parentheses table row cell negative 3 end cell row 4 end table close parentheses minus open parentheses table row 2 row 5 end table close parentheses end cell row cell open parentheses table row cell b subscript 1 minus 5 end cell row cell b subscript 2 plus 3 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 9 end cell row 12 end table close parentheses minus open parentheses table row 2 row 5 end table close parentheses end cell row cell open parentheses table row cell b subscript 1 minus 5 end cell row cell b subscript 2 plus 3 end cell end table close parentheses end cell equals cell open parentheses table row cell negative 11 end cell row 7 end table close parentheses end cell row blank rightwards arrow cell b subscript 1 equals negative 6 space dan space b subscript 2 equals 4 end cell end table

Jadi, koordinat titik B adalah left parenthesis negative 6 comma 4 right parenthesis.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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