Iklan

Iklan

Pertanyaan

Diketahui vektor a = ⎝ ⎛ ​ 1 p 3 ​ ⎠ ⎞ ​ , b = ⎝ ⎛ ​ − 1 2 − 3 ​ ⎠ ⎞ ​ , dan c = ⎝ ⎛ ​ 4 7 0 ​ ⎠ ⎞ ​ . Apabila vektor a tegak lurus vektor b , hasil dari 2 a + b − c = ....

Diketahui vektor , dan . Apabila vektor  tegak lurus vektor, hasil dari = ....

  1. begin mathsize 14px style open parentheses table row 7 row cell negative 15 end cell row 0 end table close parentheses end style

  2. begin mathsize 14px style open parentheses table row cell negative 3 end cell row cell negative 15 end cell row cell negative 6 end cell end table close parentheses end style

  3. begin mathsize 14px style open parentheses table row cell negative 3 end cell row 5 row 3 end table close parentheses end style

  4. begin mathsize 14px style open parentheses table row 7 row 5 row cell negative 6 end cell end table close parentheses end style

  5. begin mathsize 14px style open parentheses table row cell negative 3 end cell row cell negative 15 end cell row 0 end table close parentheses end style

Iklan

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Iklan

Pembahasan

begin mathsize 14px style Karena space straight a with rightwards arrow on top space tegak space lurus space straight b with rightwards arrow on top space maka  straight a with rightwards arrow on top straight space. straight space straight b with rightwards arrow on top equals 0  open parentheses table row 1 row straight p row 3 end table close parentheses straight space. straight space open parentheses table row cell negative 1 end cell row 2 row cell negative 3 end cell end table close parentheses equals 0  1 open parentheses negative 1 close parentheses plus straight p open parentheses 2 close parentheses plus 3 left parenthesis negative 3 right parenthesis equals 0  2 straight p equals 10 rightwards arrow straight p equals 5.    Maka space hasil space dari comma  2 straight a with rightwards arrow on top plus straight b with rightwards arrow on top minus straight c with rightwards arrow on top equals 2 open parentheses table row 1 row 5 row 3 end table close parentheses plus open parentheses table row cell negative 1 end cell row 2 row cell negative 3 end cell end table close parentheses minus open parentheses table row 4 row 7 row 0 end table close parentheses  2 straight a with rightwards arrow on top plus straight b with rightwards arrow on top minus straight c with rightwards arrow on top equals open parentheses table row cell negative 3 end cell row 5 row 3 end table close parentheses end style

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

30

Natasha Dwi Anandya

TENCUU DEKKU😉 doain nilai ai tinggi yes😇

Siti Rahmatia Lolai

Jawaban tidak sesuai

Iklan

Iklan

Pertanyaan serupa

Diketahui vektor d = ( 2 1 ​ ) , e = ( − 4 2 ​ ) , dan f ​ = ( 0 5 ​ ) . Tentukan hasil operasi-operasi vektor berikut. 4) − 3 d + 4 e − 2 f ​

2

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia