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Diketahui suku pertama deret geometri adalah 4 m ​ dengan m > 0 dan suku ke-7 adalah m 3 . Jika rasio deret geometri tersebut positif, maka suku ke-19 adalah ....

Diketahui suku pertama deret geometri adalah  dengan > 0 dan suku ke-7 adalah . Jika rasio deret geometri tersebut positif, maka suku ke-19 adalah ....

  1. Error converting from MathML to accessible text. 

  2. begin mathsize 14px style straight m to the power of 7 space fourth root of straight m end style 

  3. begin mathsize 14px style straight m to the power of 8 space square root of straight m end style

  4. begin mathsize 14px style straight m to the power of 8 space fourth root of straight m end style 

  5. begin mathsize 14px style straight m to the power of 9 space square root of straight m end style 

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

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Pembahasan

Diketahui bahwa terdapat barisan geometri dengan Ingat bahwa pada barisan geometri berlaku Sehigga Pada soal diketahui bahwa rasionya positif, maka Sehingga suku ke-19 yaitu Jadi, jawaban yang tepat adalah C.

Diketahui bahwa terdapat barisan geometri dengan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row straight a equals cell fourth root of straight m equals straight m to the power of 1 fourth end exponent end cell row cell straight U subscript 7 end cell equals cell straight m cubed end cell end table end style

Ingat bahwa pada barisan geometri berlaku

begin mathsize 14px style straight U subscript straight n equals ar to the power of straight n minus 1 end exponent end style 

Sehigga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight U subscript 7 end cell equals cell straight m cubed end cell row cell ar to the power of 7 minus 1 end exponent end cell equals cell straight m cubed end cell row cell straight m to the power of 1 fourth end exponent straight r to the power of 6 end cell equals cell straight m cubed end cell row cell straight r to the power of 6 end cell equals cell straight m cubed over straight m to the power of 1 fourth end exponent end cell row cell straight r to the power of 6 end cell equals cell straight m to the power of 3 minus 1 fourth end exponent end cell row cell straight r to the power of 6 end cell equals cell straight m to the power of 11 over 4 end exponent end cell row straight r equals cell plus-or-minus root index 6 of straight m to the power of 11 over 4 end exponent end root end cell row blank blank blank end table end style

Pada soal diketahui bahwa rasionya positif, maka

begin mathsize 14px style straight r equals root index 6 of straight m to the power of 11 over 4 end exponent end root straight r equals open parentheses straight m to the power of 11 over 4 end exponent close parentheses to the power of 1 over 6 end exponent straight r equals straight m to the power of 11 over 24 end exponent end style 

Sehingga suku ke-19 yaitu

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight U subscript 19 end cell equals cell ar to the power of 19 minus 1 end exponent end cell row blank equals cell ar to the power of 18 end cell row blank equals cell straight m to the power of 1 fourth end exponent open parentheses straight m to the power of 11 over 24 end exponent close parentheses to the power of 18 end cell row blank equals cell straight m to the power of 1 fourth end exponent straight m to the power of open parentheses 11 over 24 close parentheses space. space 18 end exponent end cell row blank equals cell straight m to the power of 1 fourth end exponent straight m to the power of open parentheses 11 over 4 close parentheses space. space 3 end exponent end cell row blank equals cell straight m to the power of 1 fourth end exponent straight m to the power of 33 over 4 end exponent end cell row blank equals cell straight m to the power of 1 fourth plus end exponent to the power of 33 over 4 end exponent end cell row blank equals cell straight m to the power of 34 over 4 end exponent end cell row blank equals cell straight m to the power of 17 over 2 end exponent end cell row blank equals cell straight m to the power of 16 over 2 plus 1 half end exponent end cell row blank equals cell straight m to the power of 16 over 2 end exponent space. space straight m to the power of 1 half end exponent end cell row blank equals cell straight m to the power of 8 square root of straight m end cell end table end style 

Jadi, jawaban yang tepat adalah C.

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Dalam suatu barisan geometri, U 1 ​ + U 3 ​ + U 5 ​ = s dan U 2 ​ + U 4 ​ + U 6 ​ = t . Maka U 3 ​ adalah ....

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