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Diketahui matriks-matriks berikut. A = [ 1 − 1 ​ 0 0 ​ − 1 0 ​ ] ; B = [ 2 0 ​ − 1 1 ​ 0 − 1 ​ ] ; C = [ 2 1 ​ 2 3 ​ ] Serta B T dan C − 1 berturut-turut menyatakan transpose matriks B dan invers matriks C. Jika d e t ( A B T ) = k d e t ( C − 1 ) dengan det(A) menyatakan determinan matriks A, maka nilai k adalah...

Diketahui matriks-matriks berikut.

 

Serta  dan  berturut-turut menyatakan transpose matriks B dan invers matriks C. Jika  dengan det(A) menyatakan determinan matriks A, maka nilai k adalah...

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nilai k adalah 2.

nilai k adalah 2.

Pembahasan

Diketahui: Ingat: det(A) = |A| Jika , maka terlebih dahulu cari matriks dan . Maka Sehingga Sedangkan Sehingga Jika , maka: 2 = k.1 k = 2 Jadi, nilai k adalah 2.

Diketahui:

begin mathsize 12px style A equals open square brackets table row 1 0 cell negative 1 end cell row cell negative 1 end cell 0 0 end table close square brackets semicolon space B equals open square brackets table row 2 cell negative 1 end cell 0 row 0 1 cell negative 1 end cell end table close square brackets semicolon space C equals open square brackets table row 2 2 row 1 3 end table close square brackets end style  

Ingat: det(A) = |A|

Jika begin mathsize 12px style d e t open parentheses A B to the power of T close parentheses equals k space d e t open parentheses C to the power of negative 1 end exponent close parentheses end style , maka terlebih dahulu cari matriks begin mathsize 12px style A B to the power of T end style dan begin mathsize 12px style C to the power of negative 1 end exponent end style .

begin mathsize 12px style B equals open square brackets table row 2 cell negative 1 end cell 0 row 0 1 cell negative 1 end cell end table close square brackets B to the power of T equals open square brackets table row 2 0 row cell negative 1 end cell 1 row 0 cell negative 1 end cell end table close square brackets end style  

Maka

begin mathsize 12px style A B to the power of T equals open square brackets table row 1 0 cell negative 1 end cell row cell negative 1 end cell 0 0 end table close square brackets times open square brackets table row 2 0 row cell negative 1 end cell 1 row 0 cell negative 1 end cell end table close square brackets A B to the power of T equals open square brackets table row cell 2 plus 0 plus 0 end cell cell 0 plus 0 plus 1 end cell row cell negative 2 plus 0 plus 0 end cell cell 0 plus 0 plus 0 end cell end table close square brackets A B to the power of T equals open square brackets table row 2 1 row cell negative 2 end cell 0 end table close square brackets end style  

Sehingga begin mathsize 12px style d e t open parentheses A B to the power of T close parentheses equals 2.0 minus 1 open parentheses negative 2 close parentheses equals 2 end style  

Sedangkan

begin mathsize 12px style C to the power of negative 1 end exponent equals fraction numerator 1 over denominator 2.3 minus 2.1 end fraction open square brackets table row 3 cell negative 2 end cell row cell negative 1 end cell 2 end table close square brackets C to the power of negative 1 end exponent equals 1 fourth open square brackets table row 3 cell negative 2 end cell row cell negative 1 end cell 2 end table close square brackets end style  

Sehingga

begin mathsize 12px style d e t open parentheses C to the power of negative 1 end exponent close parentheses equals 1 fourth open parentheses 3.2 minus open parentheses negative 2 close parentheses open parentheses negative 1 close parentheses close parentheses equals 1 fourth open parentheses 4 close parentheses equals 1 end style  

Jika begin mathsize 12px style d e t open parentheses A B to the power of T close parentheses equals k space d e t open parentheses C to the power of negative 1 end exponent close parentheses end style , maka:

2 = k.1

k = 2

Jadi, nilai k adalah 2.

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