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Diketahui matriks A = ⎣ ⎡ ​ − 1 0 − 3 ​ 0 2 1 ​ 3 1 0 ​ ⎦ ⎤ ​ dan B = ⎣ ⎡ ​ − 5 − 3 − 7 ​ − 1 0 − 3 ​ 3 − 3 − 2 ​ ⎦ ⎤ ​ . Tentukan nilai dari A − B T !

Diketahui matriks  dan . Tentukan nilai dari !

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Jawaban terverifikasi

Jawaban

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table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight A end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight B end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of straight T end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets table row 4 3 10 row 1 2 4 row cell negative 6 end cell 4 2 end table close square brackets end cell end table.

Pembahasan

Pembahasan
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Diketahui Maka, Jadi, .

Diketahui

table attributes columnalign right center left columnspacing 0px end attributes row straight A equals cell open square brackets table row cell negative 1 end cell 0 3 row 0 2 1 row cell negative 3 end cell 1 0 end table close square brackets comma space straight B to the power of straight T equals open square brackets table row cell negative 5 end cell cell negative 3 end cell cell negative 7 end cell row cell negative 1 end cell 0 cell negative 3 end cell row 3 cell negative 3 end cell cell negative 2 end cell end table close square brackets end cell row blank blank blank end table

Maka,

table attributes columnalign right center left columnspacing 0px end attributes row cell straight A minus straight B to the power of straight T end cell equals cell open square brackets table row cell negative 1 end cell 0 3 row 0 2 1 row cell negative 3 end cell 1 0 end table close square brackets minus open square brackets table row cell negative 5 end cell cell negative 3 end cell cell negative 7 end cell row cell negative 1 end cell 0 cell negative 3 end cell row 3 cell negative 3 end cell cell negative 2 end cell end table close square brackets end cell row blank equals cell open square brackets table row 4 3 10 row 1 2 4 row cell negative 6 end cell 4 2 end table close square brackets end cell end table

 

Jadi, table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight A end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank straight B end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of straight T end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets table row 4 3 10 row 1 2 4 row cell negative 6 end cell 4 2 end table close square brackets end cell end table.

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Diketahui P = [ − 7 − 2 ​ 1 0 ​ ] , Q = [ − 2 1 ​ 4 5 ​ ] dan R = [ − 4 0 ​ 1 − 2 ​ ] , tentukan hasil dari matriks berikut: b. 2 R 2 − 4 Q T

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