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Diketahui k = 5 ∑ 25 ​ ( 2 − p k ​ ) = − 40 , maka nilai k = 5 ∑ 25 ​ p k ​ = ....

Diketahui , maka nilai  

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W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

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Jawaban

nilai .

nilai sum from k equals 5 to 25 of space p subscript k equals 90

Pembahasan

Ingat kembali: Diketahui , maka: Jadi, nilai .

Ingat kembali:

sum from k equals 1 to n of space open parentheses m subscript k plus-or-minus n subscript k close parentheses equals sum from k equals 1 to n of space m subscript k plus-or-minus sum from k equals 1 to n of space n subscript k sum from k equals 1 to n of space a equals a times n comma space untuk space a element of R 

Diketahui sum from k equals 5 to 25 of space open parentheses 2 minus p subscript k close parentheses equals negative 40, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell sum from k equals 5 to 25 of space open parentheses 2 minus p subscript k close parentheses end cell equals cell negative 40 end cell row cell sum from k equals 5 to 25 of 2 minus sum from k equals 5 to 25 of p subscript k end cell equals cell negative 40 end cell row cell 2 times 25 minus sum from k equals 5 to 25 of p subscript k end cell equals cell negative 40 end cell row cell 50 minus sum from k equals 5 to 25 of p subscript k end cell equals cell negative 40 end cell row cell negative sum from k equals 5 to 25 of space p subscript k end cell equals cell negative 40 minus 50 end cell row cell negative sum from k equals 5 to 25 of p subscript k end cell equals cell negative 90 end cell row cell sum from k equals 5 to 25 of p subscript k end cell equals 90 end table 

Jadi, nilai sum from k equals 5 to 25 of space p subscript k equals 90

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