Roboguru

Pertanyaan

Diketahui kubus PQRS.TUVW dengan panjang rusuk 6 cm. Cosinus sudut antara bidang PUW
dengan bidang PQRS adalah ...

  1. 1 half square root of 3

  2. 1 third square root of 3

  3. 1 half square root of 6

  4. 1 third square root of 6

  5. 1 over 6 square root of 6

H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

S u d u t space a n t a r a space b i d a n g space P U W space d e n g a n space b i d a n g space P Q R S space a d a l a h space angle space A P B.  asterisk times A B space equals space P T space equals space 6 space c m  asterisk times P R space equals space a square root of 2 space end root equals space 6 square root of 2 space end root c m  asterisk times P B equals space 1 half P R space equals fraction numerator 1 space over denominator 2 end fraction left parenthesis space 6 square root of 2 right parenthesis space equals space 3 square root of 2 space c m  asterisk times P A space equals space square root of P B to the power of 2 space end exponent plus space A B squared end root  space space space space space space space space equals space square root of open parentheses 3 square root of 2 close parentheses squared plus 6 squared end root  space space space space space space space space equals space square root of 18 space plus space 36 end root space equals space square root of 54 space end root equals space square root of 9 x 6 end root space equals space 3 square root of 6 space c m  cos angle space A P B equals fraction numerator P B over denominator P A end fraction  space space space space space space space space space space space space space space space space space space space equals fraction numerator 3 square root of 2 over denominator 3 square root of 6 end fraction space x space fraction numerator square root of 6 over denominator square root of 6 end fraction space equals space space fraction numerator square root of 12 over denominator 6 end fraction  space space space space space space space space space space space space space space space space space space space equals fraction numerator space 2 square root of 3 over denominator 6 end fraction equals space 1 third square root of 3

494

0.0 (0 rating)

Pertanyaan serupa

Diketahui kubus ABCD.EFGH dengan panjang rusuk 6 cm. Nilai sin ∠(BDE,BDG) adalah ...

185

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia