Diketahui jajaran genjang ABCD dengan AC⇀=u⇀ dan BD⇀=v⇀. Nyatakan vektor-vektor berikut dalam u⇀ danv⇀. c. AB⇀

Pertanyaan

Diketahui jajaran genjang ABCD dengan size 14px AC with size 14px rightwards harpoon with barb upwards on top size 14px equals size 14px u with size 14px rightwards harpoon with barb upwards on top dan stack size 14px B size 14px D with size 14px rightwards harpoon with barb upwards on top size 14px equals size 14px v with size 14px rightwards harpoon with barb upwards on top. Nyatakan vektor-vektor berikut dalam size 14px u with size 14px rightwards harpoon with barb upwards on top dansize 14px v with size 14px rightwards harpoon with barb upwards on top.

c. stack size 14px A size 14px B with size 14px rightwards harpoon with barb upwards on top 

R. RGFLLIMA

Master Teacher

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 Error converting from MathML to accessible text..

Pembahasan

Dengan konsep perkalian vektor dengan skalar dan Operasi penjumlahan dua vektor:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell AB with rightwards harpoon with barb upwards on top end cell equals cell AO with rightwards harpoon with barb upwards on top plus OB with rightwards harpoon with barb upwards on top end cell row blank equals cell 1 half AC with rightwards harpoon with barb upwards on top plus 1 half DB with rightwards harpoon with barb upwards on top end cell row blank equals cell 1 half AC with rightwards harpoon with barb upwards on top minus 1 half BD with rightwards harpoon with barb upwards on top end cell row blank equals cell 1 half straight u with rightwards harpoon with barb upwards on top minus 1 half straight v with rightwards harpoon with barb upwards on top end cell row blank equals cell 1 half left parenthesis straight u with rightwards harpoon with barb upwards on top minus straight v with rightwards harpoon with barb upwards on top right parenthesis end cell end table end style  

Jadi, Error converting from MathML to accessible text..

41

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Avengelique Y Demervi _14

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Pada persegi panjang OACB, D adalah titik tengah OA dan P titik potong CD dengan diagonal AB. Jika a=OA dan b=OB, maka CP= ....

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