Pertanyaan

Diketahui dan . Rumus fungsi ( f + g ) ( x ) adalah ....

Diketahui $begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x plus 4 over denominator x squared minus 4 x minus 12 end fraction end style$ dan $begin mathsize 14px style g open parentheses x close parentheses equals fraction numerator negative 3 x minus 2 over denominator x squared plus 5 x plus 6 end fraction end style$ . Rumus fungsi $(f + g) (x)$ adalah ....

$begin mathsize 14px style fraction numerator negative x squared minus 10 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style$
$begin mathsize 14px style fraction numerator x squared minus 10 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style$
$begin mathsize 14px style fraction numerator negative x squared plus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style$
$begin mathsize 14px style fraction numerator x squared plus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style$
$begin mathsize 14px style fraction numerator negative x squared minus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style$

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I. Roy

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

Pembahasan

Ingat bahwa , sehingga kita peroleh Jadi, jawaban yang tepat adalah C.

Ingat bahwa , sehingga kita peroleh

$open parentheses f plus g close parentheses open parentheses x close parentheses equals f open parentheses x close parentheses plus g open parentheses x close parenthesesopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 2 x plus 4 over denominator x squared minus 4 x minus 12 end fraction plus fraction numerator negative 3 x minus 2 over denominator x squared plus 5 x plus 6 end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 2 x plus 4 over denominator open parentheses x plus 2 close parentheses open parentheses x minus 6 close parentheses end fraction plus fraction numerator negative 3 x minus 2 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator open parentheses 2 x plus 4 close parentheses open parentheses x plus 3 close parentheses plus open parentheses negative 3 x minus 2 close parentheses open parentheses x minus 6 close parentheses over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator left parenthesis 2 x squared plus 6 x plus 4 x plus 12 right parenthesis plus open parentheses negative 3 x squared plus 18 x minus 2 x plus 12 close parentheses over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 2 x squared plus 10 x plus 12 minus 3 x squared plus 16 x plus 12 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator negative x squared plus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction$

Jadi, jawaban yang tepat adalah C.