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Diketahui  dan . Rumus fungsi (f+g)(x) adalah ....

Pertanyaan

Diketahui begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x plus 4 over denominator x squared minus 4 x minus 12 end fraction end style dan begin mathsize 14px style g open parentheses x close parentheses equals fraction numerator negative 3 x minus 2 over denominator x squared plus 5 x plus 6 end fraction end style. Rumus fungsi begin mathsize 14px style left parenthesis f plus g right parenthesis left parenthesis x right parenthesis end style adalah ....

  1. begin mathsize 14px style fraction numerator negative x squared minus 10 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style

  2. begin mathsize 14px style fraction numerator x squared minus 10 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style 

  3. begin mathsize 14px style fraction numerator negative x squared plus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style 

  4. begin mathsize 14px style fraction numerator x squared plus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style 

  5. begin mathsize 14px style fraction numerator negative x squared minus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction end style 

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

Pembahasan

Ingat bahwa begin mathsize 14px style left parenthesis f plus g right parenthesis left parenthesis x right parenthesis equals f left parenthesis x right parenthesis plus g left parenthesis x right parenthesis end style, sehingga kita peroleh

open parentheses f plus g close parentheses open parentheses x close parentheses equals f open parentheses x close parentheses plus g open parentheses x close parenthesesopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 2 x plus 4 over denominator x squared minus 4 x minus 12 end fraction plus fraction numerator negative 3 x minus 2 over denominator x squared plus 5 x plus 6 end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 2 x plus 4 over denominator open parentheses x plus 2 close parentheses open parentheses x minus 6 close parentheses end fraction plus fraction numerator negative 3 x minus 2 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator open parentheses 2 x plus 4 close parentheses open parentheses x plus 3 close parentheses plus open parentheses negative 3 x minus 2 close parentheses open parentheses x minus 6 close parentheses over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator left parenthesis 2 x squared plus 6 x plus 4 x plus 12 right parenthesis plus open parentheses negative 3 x squared plus 18 x minus 2 x plus 12 close parentheses over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator 2 x squared plus 10 x plus 12 minus 3 x squared plus 16 x plus 12 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fractionopen parentheses f plus g close parentheses open parentheses x close parentheses equals fraction numerator negative x squared plus 26 x plus 24 over denominator open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses open parentheses x minus 6 close parentheses end fraction 

Jadi, jawaban yang tepat adalah C.

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Pertanyaan serupa

Diberikan  f(x)=(2x+1)(x−1) dan  g(x)=x2+3x−5. Rumus fungsi (f+g)(x) adalah ....

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