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Diketahui p  ≡ 0 dan q  ≡ 0. Bentuk sederhana dari ⎣ ⎡ ​ 2 1 ​ p q 4 3 2 − 1 p − 3 q − 4 ​ ⎦ ⎤ ​ − 1 adalah ....

Diketahui dan  Bentuk sederhana dari adalah 

  1. 2 to the power of 4 p to the power of 4 q to the power of 8 space

  2. 2 to the power of 7 p cubed q to the power of 10 space

  3. 2 cubed p squared q to the power of 8 space

  4. open parentheses 2 p q squared close parentheses squared space

  5. open parentheses 2 p squared q squared close parentheses squared space

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

jawaban yang benar adalah A.

Pembahasan

Pembahasan
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Diketahui dengan dan maka berdasarkan sifat eksponen sehingga Oleh karena itu, jawaban yang benar adalah A.

Diketahui open square brackets fraction numerator 32 to the power of negative 1 end exponent p to the power of negative 3 end exponent q to the power of negative 4 end exponent over denominator begin display style 1 half end style p q to the power of 4 end fraction close square brackets to the power of negative 1 end exponent spacedengan  p not identical to 0 spacedan q not identical to 0 comma maka berdasarkan sifat eksponen

open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent

 a to the power of m cross times a to the power of n equals a to the power of m plus n end exponent

Error converting from MathML to accessible text.

 sehingga

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets fraction numerator 32 to the power of negative 1 end exponent p to the power of negative 3 end exponent q to the power of negative 4 end exponent over denominator begin display style 1 half end style p q to the power of 4 end fraction close square brackets to the power of negative 1 end exponent end cell equals cell open square brackets fraction numerator left parenthesis 2 to the power of 5 right parenthesis to the power of negative 1 end exponent p to the power of negative 3 minus 1 end exponent q to the power of negative 4 minus 4 end exponent over denominator 2 to the power of negative 1 end exponent end fraction close square brackets to the power of negative 1 end exponent end cell row blank equals cell open square brackets fraction numerator 2 to the power of negative 5 end exponent p to the power of negative 4 end exponent q to the power of negative 8 end exponent over denominator 2 to the power of negative 1 end exponent end fraction close square brackets to the power of negative 1 end exponent end cell row blank equals cell open square brackets 2 to the power of negative 5 plus 1 end exponent p to the power of negative 4 end exponent q to the power of negative 8 end exponent close square brackets to the power of negative 1 end exponent end cell row blank equals cell open square brackets 2 to the power of negative 4 end exponent p to the power of negative 4 end exponent q to the power of negative 8 end exponent close square brackets to the power of negative 1 end exponent end cell row blank equals cell 2 to the power of 4 p to the power of 4 q to the power of 8 end cell end table


Oleh karena itu, jawaban yang benar adalah A.

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