Pertanyaan

0 , 0 1 − 2 + ( 216 1 ) − 3 2 = ....

$0, 0 1^{- 2} + (\frac{1}{216})^{- \frac{2}{3}} = ....$

W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

.

0 comma 01 to the power of negative 2 end exponent plus open parentheses 1 over 216 close parentheses to the power of negative 2 over 3 end exponent equals 10.036

Pembahasan

Ingat kembali sifat-sifat bilangan berpangkat berikut: Hasil dari dapat ditentukan sebagai berikut: Jadi, .

Ingat kembali sifat-sifat bilangan berpangkat berikut:

Hasil dari 0 comma 01 to the power of negative 2 end exponent plus open parentheses 1 over 216 close parentheses to the power of negative 2 over 3 end exponent dapat ditentukan sebagai berikut:

$table attributes columnalign right center left columnspacing 0px end attributes row cell 0 comma 01 to the power of negative 2 end exponent plus open parentheses 1 over 216 close parentheses to the power of negative 2 over 3 end exponent end cell equals cell open parentheses 1 over 100 close parentheses to the power of negative 2 end exponent plus open parentheses open parentheses 1 over 6 close parentheses cubed close parentheses to the power of negative 2 over 3 end exponent end cell row blank equals cell open parentheses open parentheses 1 over 10 close parentheses squared close parentheses to the power of negative 2 end exponent plus open parentheses open parentheses 1 over 6 close parentheses cubed close parentheses to the power of negative 2 over 3 end exponent end cell row blank equals cell open parentheses 1 over 10 close parentheses to the power of 2 cross times open parentheses negative 2 close parentheses end exponent plus open parentheses 1 over 6 close parentheses to the power of up diagonal strike 3 cross times open parentheses negative fraction numerator 2 over denominator up diagonal strike 3 end fraction close parentheses end exponent end cell row blank equals cell open parentheses 1 over 10 close parentheses to the power of negative 4 end exponent plus open parentheses 1 over 6 close parentheses to the power of negative 2 end exponent end cell row blank equals cell 1 over open parentheses 1 over 10 close parentheses to the power of 4 plus 1 over open parentheses 1 over 6 close parentheses squared end cell row blank equals cell fraction numerator 1 over denominator begin display style 1 to the power of 4 over 10 to the power of 4 end style end fraction plus fraction numerator 1 over denominator begin display style 1 squared over 6 squared end style end fraction end cell row blank equals cell fraction numerator 1 over denominator begin display style fraction numerator 1 over denominator 10.000 end fraction end style end fraction plus fraction numerator 1 over denominator begin display style 1 over 36 end style end fraction end cell row blank equals cell open parentheses 1 cross times fraction numerator 10.000 over denominator 1 end fraction close parentheses plus open parentheses 1 cross times 36 over 1 close parentheses end cell row blank equals cell 10.000 plus 36 end cell row blank equals cell 10.036 end cell end table$

Jadi, 0 comma 01 to the power of negative 2 end exponent plus open parentheses 1 over 216 close parentheses to the power of negative 2 over 3 end exponent equals 10.036 .