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Pertanyaan

Data percobaan yang diperoleh dari reaksi: A and B yields C sebagai berikut.

 

Laju reaksi tersebut dinyatakan dengan persamaan ...space

  1. italic v equals 0 comma 6 open square brackets A close square brackets squared open square brackets B close square brackets space space space

  2. italic v equals 6 open square brackets A close square brackets open square brackets B close square brackets space space space

  3. italic v equals 6 open square brackets A close square brackets open square brackets B close square brackets squared space space space

  4. italic v equals 0 comma 6 open square brackets B close square brackets squared space space space

  5. italic v equals 6 open square brackets A close square brackets squared space space space

I. Solichah

Master Teacher

Jawaban terverifikasi

Pembahasan

Berikut langkah-langkah menentukan persamaan laju reaksi untuk reaksi:

A and B yields C 

  1. Menghitung orde reaksi A

    Untuk menghitung orde reaksi A, gunakan data 2 percobaan dengan konsentrasi B sama, misal percobaan (1) dan (2).

    v subscript 1 over v subscript 2 equals fraction numerator italic k open square brackets italic A close square brackets subscript 1 superscript italic x open square brackets B close square brackets subscript 1 superscript italic y over denominator italic k open square brackets italic A close square brackets subscript 2 superscript italic x open square brackets B close square brackets subscript 2 superscript italic y end fraction fraction numerator 0 comma 006 over denominator 0 comma 018 end fraction equals fraction numerator up diagonal strike italic k open parentheses 0 comma 1 close parentheses to the power of x up diagonal strike italic left parenthesis italic 0 italic comma italic 1 italic right parenthesis to the power of italic y end strike over denominator up diagonal strike italic k open parentheses 0 comma 3 close parentheses to the power of x up diagonal strike begin italic style left parenthesis 0 comma 1 right parenthesis end style to the power of italic y end strike end fraction 1 third equals open parentheses 1 third close parentheses to the power of x x equals 1 
     
  2. Menghitung orde reaksi B

    Misal menggunakan data percobaan (2) dan (3)

    v subscript 2 over v subscript 3 equals fraction numerator italic k open square brackets italic A close square brackets subscript 2 superscript italic x open square brackets B close square brackets subscript 2 superscript italic y over denominator italic k open square brackets italic A close square brackets subscript 3 superscript italic x open square brackets B close square brackets subscript 3 superscript italic y end fraction fraction numerator 0 comma 018 over denominator 0 comma 048 end fraction equals fraction numerator up diagonal strike italic k open parentheses 0 comma 3 close parentheses open parentheses 0 comma 1 close parentheses to the power of y over denominator up diagonal strike italic k open parentheses 0 comma 2 close parentheses open parentheses 0 comma 2 close parentheses to the power of y end fraction 3 over 8 equals open parentheses 3 over 2 close parentheses open parentheses 1 half close parentheses to the power of y 3 over 8 cross times 2 over 3 equals open parentheses 1 half close parentheses to the power of y 1 fourth equals open parentheses 1 half close parentheses to the power of y y equals 2 
     
  3. Menghitung konstanta laju reaksi

    Misal menggunakan data percobaan (1)

    v subscript 1 equals italic k open square brackets italic A close square brackets subscript 1 superscript italic x open square brackets B close square brackets subscript 1 superscript italic y 0 comma 006 equals italic k open parentheses 0 comma 1 close parentheses open parentheses 0 comma 1 close parentheses squared italic k equals fraction numerator 0 comma 006 over denominator 0 comma 001 end fraction italic k equals 6 
     
  4. Menuliskan persamaan laju reaksi

    v equals italic k open square brackets italic A close square brackets to the power of italic x open square brackets B close square brackets to the power of italic y v equals 6 begin italic style left square bracket italic A right square bracket end style begin italic style open square brackets B close square brackets end style to the power of italic 2 


Jadi, jawaban yang tepat adalah C.space space space

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Jawaban terverifikasi

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