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Dalam 200 mL larutan terdapat 2 × 1 0 − 5 mol Mg ( OH ) 2 ​ jenuh. Kelarutan Mg ( OH ) 2 ​ dalam larutan dengan pH = 12 + lo g 2 adalah ....

Dalam 200 mL larutan terdapat jenuh. Kelarutan dalam larutan dengan  adalah ....

 

  1. begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 2 end exponent space M end style

  2. begin mathsize 14px style 0 comma 5 cross times 10 to the power of negative sign 3 end exponent space M end style

  3. begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 8 end exponent space M end style

  4. begin mathsize 14px style 2 comma 0 cross times 10 to the power of negative sign 8 end exponent space M end style

  5. begin mathsize 14px style 4 comma 0 cross times 10 to the power of negative sign 8 end exponent space M end style

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I. Yassa

Master Teacher

Jawaban terverifikasi

Pembahasan

Pembahasan
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Diketahui: Berikut langkah penyelesaiannya: Mencari Ksp Mencari Mencari kelarutan Jadi, jawaban yang benar adalah C.

Diketahui:

undefined

Berikut langkah penyelesaiannya:

  1. Mencari Ksp

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row M equals cell n over V end cell row blank equals cell fraction numerator 2 cross times 10 to the power of negative sign 5 space end exponent mol over denominator 0 comma 2 space L end fraction end cell row blank equals cell 10 to the power of negative sign 4 end exponent space M end cell end table end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell open parentheses s close parentheses cross times left parenthesis 2 s right parenthesis squared equals 4 left parenthesis 10 to the power of negative sign 4 end exponent right parenthesis cubed space equals 4 cross times 10 to the power of negative sign 12 end exponent end cell end table end style 
     
  2. Mencari begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell 14 minus sign pH end cell row blank equals cell 14 minus sign left parenthesis 12 plus log space 2 right parenthesis end cell row blank equals cell 2 minus sign log space 2 end cell end table end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell 2 minus sign log space 2 end cell equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 2 cross times 10 to the power of negative sign 2 space end exponent M end cell end table end style
     
  3. Mencari kelarutan begin mathsize 14px style Mg open parentheses O H close parentheses subscript 2 end style

    begin mathsize 14px style Mg open parentheses O H close parentheses subscript 2 equilibrium Mg to the power of 2 plus sign and 2 O H to the power of minus sign end style 
    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell 4 cross times 10 to the power of negative sign 12 end exponent end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets space left parenthesis 2 cross times 10 to the power of negative sign 2 end exponent right parenthesis squared end cell row cell open square brackets Mg to the power of 2 plus sign close square brackets end cell equals cell 1 cross times 10 to the power of negative sign 8 end exponent space M end cell end table end style

Jadi, jawaban yang benar adalah C.
 

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