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Berkas elektron berkecepatan 1,1×106 m/s. Jika massa elektron dan konstanta Planck masing-masing 9×10−31 kgdan 6,6×10−34 Js, maka panjang gelombang berkas elektron tersebut adalah...

Pertanyaan

Berkas elektron berkecepatan begin mathsize 14px style 1 comma 1 cross times 10 to the power of 6 space straight m divided by straight s end style. Jika massa elektron dan konstanta Planck masing-masing begin mathsize 14px style 9 cross times 10 to the power of negative 31 end exponent space kg end styledan begin mathsize 14px style 6 comma 6 cross times 10 to the power of negative 34 end exponent space Js end style, maka panjang gelombang berkas elektron tersebut adalah... space

  1. begin mathsize 14px style 6 comma 6 cross times 10 to the power of negative 10 end exponent space straight m end style 

  2. begin mathsize 14px style 6 comma 5 cross times 10 to the power of negative 10 end exponent space straight m end style 

  3. begin mathsize 14px style 3 comma 6 cross times 10 to the power of negative 10 end exponent space straight m end style 

  4. begin mathsize 14px style 6 comma 0 cross times 10 to the power of negative 10 end exponent space straight m end style 

U. Amalia

Master Teacher

Mahasiswa/Alumni UIN Sunan Gunung Djati Bandung

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.space

Pembahasan

Diketahui :

v1 comma 1 cross times 10 to the power of 6 space straight m divided by straight s
m9 cross times 10 to the power of negative 31 end exponent space kg
h6 comma 6 cross times 10 to the power of negative 34 end exponent space Js

Ditanyakan lambda ... ?

Jawab :

Panjang gelombang dapat dicari dengan persamaan berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row lambda equals cell h over p end cell row blank equals cell fraction numerator h over denominator m v end fraction end cell row blank equals cell fraction numerator 6 comma 6 cross times 10 to the power of negative 34 end exponent over denominator 9 cross times 10 to the power of negative 31 end exponent cross times 1 comma 1 cross times 10 to the power of 6 end fraction end cell row blank equals cell 0 comma 66 cross times 10 to the power of negative 9 end exponent end cell row blank equals cell 6 comma 6 cross times 10 to the power of negative 10 end exponent space straight m end cell end table end style 

Jadi, jawaban yang benar adalah A.space

1rb+

4.5 (2 rating)

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