Roboguru

Sebuah elektron bermassa  dipercepat melalui beda potensial sebesar 500 V. Jika muatan elektron  dan konstanta Planck , panjang gelombang de Broglie elektron tersebut adalah ...

Pertanyaan

Sebuah elektron bermassa begin mathsize 14px style 9 cross times 10 to the power of negative 31 end exponent space kg end style dipercepat melalui beda potensial sebesar 500 V. Jika muatan elektron begin mathsize 14px style 1 comma 6 cross times 10 to the power of negative 19 end exponent space straight C end style dan konstanta Planck begin mathsize 14px style 6 comma 6 cross times 10 to the power of negative 34 end exponent space Js end style, panjang gelombang de Broglie elektron tersebut adalah ...

  1. 42 pmspace 

  2. 55 pmundefined 

  3. 63 pmundefined 

  4. 74 pmundefined 

  5. 86 pmundefined 

Pembahasan Video:

Pembahasan Soal:

Diketahui : 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row m equals cell 9 comma 1 cross times 10 to the power of negative 31 end exponent space kg end cell row V equals cell 500 space V end cell row e equals cell 1 comma 6 cross times 10 to the power of negative 19 end exponent space straight C end cell row h equals cell 6 comma 6 cross times 10 to the power of negative 34 end exponent space Js end cell end table end style  

Ditanya : begin mathsize 14px style lambda end style 

Hubungan Energi kinetik dan momentum

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript k end cell equals cell 1 half m v squared end cell row cell e space V end cell equals cell fraction numerator p over denominator 2 m end fraction squared end cell row p equals cell square root of 2 m e V end root end cell end table end style 

Panjang gelombang de Broglie elektron tersebut 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row lambda equals cell fraction numerator h over denominator square root of 2 m e V end root end fraction end cell row lambda equals cell fraction numerator 6 comma 6 cross times 10 to the power of negative 34 end exponent over denominator square root of 2. space 9 cross times 10 to the power of negative 31 end exponent.1 comma 6 cross times 10 to the power of negative 19 end exponent.500 end root end fraction end cell row lambda equals cell fraction numerator 6 comma 6 cross times 10 to the power of negative 34 end exponent over denominator square root of 144 cross times 10 to the power of negative 48 end exponent end root end fraction end cell row lambda equals cell fraction numerator 6 comma 6 cross times 10 to the power of negative 34 end exponent over denominator 12 to the power of negative 24 end exponent end fraction end cell row lambda equals cell 55 cross times 10 to the power of negative 12 end exponent space straight m end cell row lambda equals cell 55 space pm end cell end table end style 

Jadi, jawaban yang benar adalah B.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 April 2021

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