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Berapa massa Na 2 ​ CO 3 ​ yang harus ditambahkan ke dalam 100 mL larutan MgCl 2 ​ 0,002 M agar mulai terbentuk endapan? ( K sp ​ MgCO 3 ​ = 6 × 1 0 − 6 , A r ​ : Mg = 24 g mol − 1 , C = 12 g mol − 1 , O = 16 g mol − 1 , dan Na = 23 g mol − 1 )

Berapa massa  yang harus ditambahkan ke dalam 100 mL larutan 0,002 M agar mulai terbentuk endapan? , dan  

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S. Oktasari

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Jadi, massa yang mengendap adalah .

begin mathsize 14px style Mg Cl subscript 2 open parentheses italic s close parentheses rightwards arrow Mg to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis 2 space x 10 to the power of italic minus sign italic 3 end exponent italic space italic space italic space italic space 2 space x 10 to the power of italic minus sign italic 3 end exponent italic space  Mg Cl subscript 2 open parentheses italic s close parentheses rightwards harpoon over leftwards harpoon Mg to the power of 2 plus sign left parenthesis italic a italic q right parenthesis space plus space C O subscript 3 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript italic s italic p end subscript italic space end cell equals cell open square brackets Mg to the power of 2 plus sign close square brackets left square bracket C O subscript 3 to the power of 2 minus sign end exponent right square bracket end cell row cell 6 space x 10 to the power of italic minus sign italic 6 end exponent end cell equals cell left parenthesis 2 space x 10 to the power of italic minus sign 3 end exponent right parenthesis left square bracket C O subscript 3 to the power of 2 minus sign end exponent right square bracket end cell row cell left square bracket C O subscript 3 to the power of 2 minus sign end exponent right square bracket end cell equals cell 3 space x 10 to the power of italic minus sign 3 end exponent end cell end table  Mg C O subscript 3 open parentheses italic s close parentheses rightwards arrow Mg to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus C O subscript 3 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis 3 space x 10 to the power of italic minus sign 3 end exponent space M space space space space space space space space space space space space space space space space space space space space space space space space space space 3 space x 10 to the power of italic minus sign 3 end exponent space M  space space space space space space space space space space space space space space space space space space space M equals fraction numerator massa space Mg C O subscript 3 over denominator Mr space Mg C O subscript 3 end fraction cross times 1000 over V space space space space space space space space space space 3 space x 10 to the power of italic minus sign 3 end exponent equals space fraction numerator massa space Mg C O subscript 3 over denominator 84 end fraction cross times 1000 over 100 space massa space Mg C O subscript 3 equals 0 comma 0252 space gram  end style

Jadi, massa begin mathsize 14px style Mg C O subscript bold 3 end style yang mengendap adalah begin mathsize 14px style bold 0 bold comma bold 0252 bold space bold gram end style.

 

 

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Garam kalsium oksalat ( CaC 2 ​ O 4 ​ ) dan magnesium oksalat ( MgC 2 ​ O 4 ​ ) adalah garam yang sukar larut dalam air. Bila diketahui K sp ​ CaC 2 ​ O 4 ​ = 2 , 3 × 1 0 − 9 dan K sp ​ MgC 2 ​ O 4 ​ ...

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