Iklan

Iklan

Pertanyaan

Bentuk sederhana dari ( a 4 b − 6 c − 5 a 4 b − 5 c − 6 ​ ) 3 adalah ....

Bentuk sederhana dari  adalah ....

  1. open parentheses straight b over ac close parentheses to the power of negative 3 end exponent 

  2. open parentheses straight b over straight c close parentheses to the power of negative 3 end exponent 

  3. open parentheses 1 over ab close parentheses to the power of negative 3 end exponent 

  4. open parentheses straight c over straight b close parentheses to the power of negative 3 end exponent 

  5. open parentheses ab over straight c close parentheses to the power of negative 3 end exponent 

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah D.

jawaban yang benar adalah D.

Iklan

Pembahasan

Pembahasan
lock

Ingat Kembali: Maka: Jadi, jawaban yang benar adalah D.

Ingat Kembali:

straight a to the power of straight m space colon space straight b to the power of straight n equals straight a to the power of straight m minus straight n end exponent straight a to the power of negative straight n end exponent equals 1 over straight a to the power of straight n open parentheses straight a to the power of straight m close parentheses to the power of straight n equals straight a to the power of straight m cross times straight n end exponent 

Maka:

open parentheses fraction numerator straight a to the power of 4 straight b to the power of negative 5 end exponent straight c to the power of negative 6 end exponent over denominator straight a to the power of 4 straight b to the power of negative 6 end exponent straight c to the power of negative 5 end exponent end fraction close parentheses cubed equals open parentheses straight a to the power of 4 minus 4 end exponent times straight b to the power of negative 5 minus open parentheses negative 6 close parentheses end exponent times straight c to the power of negative 6 minus open parentheses negative 5 close parentheses end exponent close parentheses cubed space space space space space space space space space space space space space space space space space space space space space equals open parentheses straight a to the power of 0 times straight b to the power of 1 times straight c to the power of negative 1 end exponent close parentheses cubed space space space space space space space space space space space space space space space space space space space space space equals straight a to the power of 0 times straight b cubed times straight c to the power of negative 3 end exponent space space space space space space space space space space space space space space space space space space space space space equals 1 times 1 over straight b to the power of negative 3 end exponent times straight c to the power of negative 3 end exponent space space space space space space space space space space space space space space space space space space space space space equals straight c to the power of negative 3 end exponent over straight b to the power of negative 3 end exponent space space space space space space space space space space space space space space space space space space space space space equals open parentheses straight c over straight b close parentheses to the power of negative 3 end exponent 

Jadi, jawaban yang benar adalah D.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

18

Iklan

Iklan

Pertanyaan serupa

Tentukan hasil pemangkatan bilangan-bilangan berikut! 4. ( 3 b 2 2 a 3 ​ ) − 4

45

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia