Iklan

Iklan

Pertanyaan

Tentukan hasil pemangkatan bilangan-bilangan berikut! 4. ( 3 b 2 2 a 3 ​ ) − 4

Tentukan hasil pemangkatan bilangan-bilangan berikut!

4.

Iklan

D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

Jawaban terverifikasi

Jawaban

hasil dari adalah .

hasil dari open parentheses fraction numerator 2 a cubed over denominator 3 b squared end fraction close parentheses to the power of negative 4 end exponent adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 81 b to the power of 8 over denominator 16 a to the power of 12 end fraction end cell end table.

Iklan

Pembahasan

Sebelum menjawab soal, ingatlah sifat-sifat bilangan berpangkat berikut. Berdasarkan sifat-sifat di atas, maka: Dengan demikian, hasil dari adalah .

Sebelum menjawab soal, ingatlah sifat-sifat bilangan berpangkat berikut.

left parenthesis straight i right parenthesis space open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent left parenthesis ii right parenthesis space a to the power of negative m end exponent equals 1 over a to the power of m left parenthesis iii right parenthesis space open parentheses a b close parentheses to the power of m equals a to the power of m b to the power of m left parenthesis iv right parenthesis space open parentheses a over b close parentheses to the power of m equals a to the power of m over b to the power of m

Berdasarkan sifat-sifat di atas, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 2 a cubed over denominator 3 b squared end fraction close parentheses to the power of negative 4 end exponent end cell equals cell 1 over open parentheses fraction numerator 2 a cubed over denominator 3 b squared end fraction close parentheses to the power of 4 end cell row blank equals cell open parentheses fraction numerator 3 b squared over denominator 2 a cubed end fraction close parentheses to the power of 4 end cell row blank equals cell open parentheses 3 b squared close parentheses to the power of 4 over open parentheses 2 a cubed close parentheses to the power of 4 end cell row blank equals cell fraction numerator 3 to the power of 4 b to the power of 2 cross times 4 end exponent over denominator 2 to the power of 4 a to the power of 3 cross times 4 end exponent end fraction end cell row blank equals cell fraction numerator 3 to the power of 4 b to the power of 8 over denominator 2 to the power of 4 a to the power of 12 end fraction end cell row blank equals cell fraction numerator 81 b to the power of 8 over denominator 16 a to the power of 12 end fraction end cell end table

Dengan demikian, hasil dari open parentheses fraction numerator 2 a cubed over denominator 3 b squared end fraction close parentheses to the power of negative 4 end exponent adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 81 b to the power of 8 over denominator 16 a to the power of 12 end fraction end cell end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

45

Iklan

Iklan

Pertanyaan serupa

Bentuk sederhana dari ( 32 p 2 q − 1 r 6 4 p − 1 q 2 r 3 ​ ) − 1 adalah....

12

4.3

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia