Pertanyaan

Bentuk sederhana dari ( ( 2 a ) 3 b 2 ) − 2 ( a 2 b − 2 ) 5 adalah ....

Bentuk sederhana dari $\frac{( a ^{2} b ^{- 2} ) ^{5}}{( ( 2 a ) ^{3} b ^{2} ) ^{- 2}}$ adalah ....

$fraction numerator 64 a to the power of 16 over denominator b to the power of 6 end fraction$
$fraction numerator a to the power of 7 over denominator 8 b to the power of 24 end fraction$
$fraction numerator a to the power of 10 over denominator 64 b to the power of 14 end fraction$
$fraction numerator 64 a b to the power of 10 over denominator b to the power of negative 6 end exponent end fraction$

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Klaim

Y. Fathoni

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta.

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Ingat kembali konsep bilangan berpangkat. Akan ditentukan bentuk sederhana dari . Diperoleh . Jadi, jawaban yang tepat adalah A.

Ingat kembali konsep bilangan berpangkat.

Akan ditentukan bentuk sederhana dari open parentheses a squared b to the power of negative 2 end exponent close parentheses to the power of 5 over open parentheses open parentheses 2 a close parentheses cubed b squared close parentheses to the power of negative 2 end exponent .

$table attributes columnalign right center left columnspacing 2px end attributes row cell open parentheses a squared b to the power of negative 2 end exponent close parentheses to the power of 5 over open parentheses open parentheses 2 a close parentheses cubed b squared close parentheses to the power of negative 2 end exponent end cell equals cell fraction numerator open parentheses a squared close parentheses to the power of 5 open parentheses b to the power of negative 2 end exponent close parentheses to the power of 5 over denominator open parentheses 8 a cubed b squared close parentheses to the power of negative 2 end exponent end fraction end cell row blank equals cell fraction numerator a to the power of 2 cross times 5 end exponent b to the power of negative 2 cross times 5 end exponent over denominator open parentheses 8 a cubed close parentheses to the power of negative 2 end exponent open parentheses b squared close parentheses to the power of negative 2 end exponent end fraction end cell row blank equals cell fraction numerator a to the power of 10 b to the power of negative 10 end exponent over denominator 8 to the power of negative 2 end exponent a to the power of 3 cross times open parentheses negative 2 close parentheses end exponent b to the power of 2 cross times open parentheses negative 2 close parentheses end exponent end fraction end cell row blank equals cell fraction numerator 8 squared a to the power of 10 b to the power of negative 10 end exponent over denominator a to the power of negative 6 end exponent b to the power of negative 4 end exponent end fraction end cell row blank equals cell 64 times a to the power of 10 over a to the power of negative 6 end exponent times b to the power of negative 10 end exponent over b to the power of negative 4 end exponent end cell row blank equals cell 64 a to the power of 10 minus open parentheses negative 6 close parentheses end exponent b to the power of negative 10 minus open parentheses negative 4 close parentheses end exponent end cell row blank equals cell 64 a to the power of 10 plus 6 end exponent b to the power of negative 10 plus 4 end exponent end cell row blank equals cell 64 a to the power of 16 b to the power of negative 6 end exponent end cell row blank equals cell fraction numerator 64 a to the power of 16 over denominator b to the power of 6 end fraction end cell end table$

Diperoleh $open parentheses a squared b to the power of negative 2 end exponent close parentheses to the power of 5 over open parentheses open parentheses 2 a close parentheses cubed b squared close parentheses to the power of negative 2 end exponent equals fraction numerator 64 a to the power of 16 over denominator b to the power of 6 end fraction$ .

Jadi, jawaban yang tepat adalah A.