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Bentuk sederhana dari 9a−1b53(ab)2c−3​ adalah ...

Pertanyaan

Bentuk sederhana dari fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction adalah ...space 

  1. a over open parentheses b c close parentheses cubed 

  2. open parentheses fraction numerator a over denominator b c end fraction close parentheses cubed 

  3. fraction numerator a over denominator b c cubed end fraction 

  4. 3 open parentheses fraction numerator a over denominator b c end fraction close parentheses cubed 

  5. 1 third open parentheses fraction numerator a over denominator b c end fraction close parentheses cubed 

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Sifat Bilangan Berpangkat.

table attributes columnalign right center left columnspacing 0px end attributes row cell a to the power of negative m end exponent end cell equals cell 1 over a to the power of m end cell row cell a to the power of m over a to the power of n end cell equals cell a to the power of m minus n end exponent end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m times n end exponent end cell end table 

Diketahui fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction.

Bentuk sederhana dari fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 3 open parentheses a b close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction end cell equals cell fraction numerator 3 open parentheses a to the power of 1 b to the power of 1 close parentheses squared c to the power of negative 3 end exponent over denominator 9 a to the power of negative 1 end exponent b to the power of 5 end fraction end cell row blank equals cell 1 third times fraction numerator a squared b squared c to the power of negative 3 end exponent over denominator a to the power of negative 1 end exponent b to the power of 5 end fraction end cell row blank equals cell 1 third times fraction numerator a to the power of 2 minus open parentheses negative 1 close parentheses end exponent over denominator b to the power of 5 minus 2 end exponent c cubed end fraction end cell row blank equals cell 1 third times fraction numerator a cubed over denominator b cubed c cubed end fraction end cell row blank equals cell 1 third open parentheses fraction numerator a over denominator b c end fraction close parentheses cubed end cell end table 

Sehingga, Error converting from MathML to accessible text..

Jadi, jawaban yang tepat adalah E.

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