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Bentuk sederhana dari (32p2q−1r64p−1q2r3​)−1 adalah....

Pertanyaan

Bentuk sederhana dari open parentheses fraction numerator 4 p to the power of negative 1 end exponent q squared r cubed over denominator 32 p squared q to the power of negative 1 end exponent r to the power of 6 end fraction close parentheses to the power of negative 1 end exponent adalah....

  1.  8 p cubed q to the power of negative 3 end exponent r cubed

  2. 8 p q r squared

  3. 8 p q r to the power of negative 3 end exponent

  4. 1 over 8 p cubed q to the power of negative 3 end exponent r cubed

  5. 1 over 8 p q r squared

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

Pembahasan

Sifat bilangan berpangkat yang digunakan:
1. space open parentheses a to the power of m close parentheses to the power of n equals a to the power of m n end exponent 2. space a to the power of m divided by a to the power of n equals a to the power of m minus n end exponent   

Dengan menggunakan sifat operasi bilangan berpangkat diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 4 p to the power of negative 1 end exponent q squared r cubed over denominator 32 p squared q to the power of negative 1 end exponent r to the power of 6 end fraction close parentheses to the power of negative 1 end exponent end cell equals cell fraction numerator 32 p squared q to the power of negative 1 end exponent r to the power of 6 over denominator 4 p to the power of negative 1 end exponent q squared r cubed end fraction end cell row blank equals cell 32 over 4 p to the power of 2 minus open parentheses negative 1 close parentheses end exponent q to the power of negative 1 minus 2 end exponent r to the power of 6 minus 3 end exponent end cell row blank equals cell 8 p cubed q to the power of negative 3 end exponent r cubed end cell end table

Oleh karena itu, jawaban yang benar adalah A.

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