Roboguru

Anggap suatu partikel bermassa 0,05 kg bergerak dengan kecepatan 0,3c . Hitunglah berapa energi kinetik partikel itu!

Pertanyaan

Anggap suatu partikel bermassa 0,05 kg bergerak dengan kecepatan 0,3c . Hitunglah berapa energi kinetik partikel itu!undefined 

  1. ....undefined 

  2. ....undefined 

Pembahasan Soal:

Eneegi kinetik relatiivistik:

begin mathsize 14px style E subscript k equals E minus E subscript o E subscript k equals fraction numerator m subscript o c squared over denominator square root of 1 minus begin display style v squared over c squared end style end root end fraction minus m subscript o c squared E subscript k equals fraction numerator m subscript o c squared over denominator square root of 1 minus begin display style open parentheses 0 comma 3 c close parentheses squared over c squared end style end root end fraction minus m subscript o c squared E subscript k equals fraction numerator m subscript o c squared over denominator square root of 1 minus begin display style fraction numerator 0 comma 09 c squared over denominator c squared end fraction end style end root end fraction minus m subscript o c squared E subscript k equals fraction numerator m subscript o c squared over denominator square root of 0 comma 91 end root end fraction minus m subscript o c squared E subscript k equals fraction numerator m subscript o c squared over denominator 0 comma 954 end fraction minus m subscript o c squared E subscript k equals m subscript o c squared open parentheses fraction numerator 1 over denominator 0 comma 954 end fraction minus 1 close parentheses E subscript k equals 0 comma 05 times open parentheses 3 cross times 10 to the power of 8 close parentheses squared times open parentheses 0 comma 048 close parentheses E subscript k equals 0 comma 05 times 9 cross times 10 to the power of 16 times open parentheses 0 comma 048 close parentheses E subscript k equals 0 comma 0217 times 9 cross times 10 to the power of 16 E subscript k equals 2 comma 17 times 9 cross times 10 to the power of 14 space straight J end style  

Jadi, energi kinetik partikel adalah 2,17x1014 J.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

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