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Pertanyaan

∫ 0 5 ​ x ( x + 1 ) ( x − 3 ) d x = ...

  

  1. negative 22 over 3

  2. 171 over 4  

  3. 425 over 12 

  4. 21 

  5. 32 

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A. Armanda

Master Teacher

Mahasiswa/Alumni Universitas Indraprasta PGRI

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

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Pembahasan

Ingat! Diketahui , maka nilai integral tersebut: Sehingga, . Jadi, jawaban yang tepat adalah C.

Ingat!

table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript a superscript b open parentheses f open parentheses x close parentheses plus-or-minus g open parentheses x close parentheses close parentheses space d x end cell equals cell integral subscript a superscript b f open parentheses x close parentheses space d x plus-or-minus integral subscript a superscript b g open parentheses x close parentheses space d x end cell row cell integral subscript a superscript b k times f open parentheses x close parentheses space d x end cell equals cell k integral subscript a superscript b f open parentheses x close parentheses space d x end cell row cell integral subscript a superscript b a x to the power of n space d x end cell equals cell open square brackets fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent close square brackets subscript a superscript b end cell end table 

Diketahuispace integral subscript 0 superscript 5 x open parentheses x plus 1 close parentheses open parentheses x minus 3 close parentheses space d x, maka nilai integral tersebut:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell space integral subscript 0 superscript 5 x open parentheses x plus 1 close parentheses open parentheses x minus 3 close parentheses space d x end cell row blank equals cell space integral subscript 0 superscript 5 x cubed minus 2 x squared minus 3 x space d x end cell row blank equals cell space integral subscript 0 superscript 5 x cubed space d x minus 2 space integral subscript 0 superscript 5 x squared space d x minus 3 space integral subscript 0 superscript 5 x space d x end cell row blank equals cell 1 fourth open square brackets x to the power of 4 close square brackets subscript 0 superscript 5 minus 2 over 3 open square brackets x cubed close square brackets subscript 0 superscript 5 minus 3 over 2 open square brackets x squared close square brackets subscript 0 superscript 5 end cell row blank equals cell 1 fourth open parentheses 5 to the power of 4 minus 0 to the power of 4 close parentheses minus 2 over 3 open parentheses 5 cubed minus 0 cubed close parentheses minus 3 over 2 open parentheses 5 squared minus 0 squared close parentheses end cell row blank equals cell 625 over 4 minus 250 over 3 minus 75 over 2 end cell row blank equals cell 425 over 12 end cell end table  

Sehingga, space integral subscript 0 superscript 5 x open parentheses x plus 1 close parentheses open parentheses x minus 3 close parentheses space d x equals 425 over 12.

Jadi, jawaban yang tepat adalah C.

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