Pertanyaan

x → 0 lim cos 3 xtan 3 1 x cot 2 x − csc 2 x = ...

$x \to 0 lim \frac{cot 2 x - csc 2 x}{cos 3 xtan \frac{1}{3} x} = ...$

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

Klaim

F. Freelancer6

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

Pembahasan

Perhatikan hasil perhitungan sebagai berikut. Jadi, jawaban yang tepat adalah E.

Perhatikan hasil perhitungan sebagai berikut.

$begin mathsize 14px style limit as straight x rightwards arrow 0 of invisible function application fraction numerator cot invisible function application 2 straight x minus csc invisible function application 2 straight x over denominator cos invisible function application 3 xtan invisible function application 1 third straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application fraction numerator fraction numerator cos invisible function application 2 straight x over denominator sin invisible function application 2 straight x end fraction minus fraction numerator 1 over denominator sin invisible function application 2 straight x end fraction over denominator cos invisible function application 3 xtan invisible function application 1 third straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application fraction numerator cos invisible function application 2 straight x minus 1 over denominator sin invisible function application 2 xcos invisible function application 3 xtan invisible function application 1 third straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application fraction numerator negative 2 sin squared invisible function application straight x over denominator 2 sin invisible function application xcos invisible function application xcos invisible function application 3 xtan invisible function application 1 third straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application fraction numerator negative sin invisible function application straight x over denominator cos invisible function application xcos invisible function application 3 xtan invisible function application 1 third straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application fraction numerator negative 1 over denominator cos invisible function application xcos invisible function application 3 straight x end fraction cross times limit as straight x rightwards arrow 0 of invisible function application fraction numerator sin invisible function application straight x over denominator tan invisible function application 1 third straight x end fraction equals negative 1 cross times fraction numerator 1 over denominator 1 third end fraction equals negative 3 end style$

Jadi, jawaban yang tepat adalah E.