Iklan

Iklan

Pertanyaan

x → 1 lim ​ 3 x 2 + 8 x + 5 2 x 2 − x − 3 ​ = ....

Iklan

Y. Umi

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

.

 limit as x rightwards arrow 1 of fraction numerator 2 x squared minus x minus 3 over denominator 3 x squared plus 8 x plus 5 end fraction equals negative 1 over 8.

Iklan

Pembahasan

Menentukan limit dengan metode pemfaktoran Jadi, .

Menentukan limit dengan metode pemfaktoran

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator 2 x squared minus x minus 3 over denominator 3 x squared plus 8 x plus 5 end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses 2 x minus 3 close parentheses open parentheses x plus 1 close parentheses over denominator open parentheses 3 x plus 5 close parentheses open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses 2 x minus 3 close parentheses over denominator open parentheses 3 x plus 5 close parentheses end fraction end cell row blank equals cell fraction numerator open parentheses 2 open parentheses 1 close parentheses minus 3 close parentheses over denominator open parentheses 3 open parentheses 1 close parentheses plus 5 close parentheses end fraction end cell row blank equals cell fraction numerator negative 1 over denominator 8 end fraction end cell end table

Jadi, limit as x rightwards arrow 1 of fraction numerator 2 x squared minus x minus 3 over denominator 3 x squared plus 8 x plus 5 end fraction equals negative 1 over 8.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4

Febby Fiang

Makasih ❤️

Iklan

Iklan

Pertanyaan serupa

Selidiki fungsi tersebut mempunyai limit atau tidak x → 1 lim ​ x 2 − 1 x 4 − 1 ​ ,berikan alasan!

10

4.3

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia