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Pertanyaan

x ↔ 2 lim ​ x 2 + 2 x + 1 x 2 − 4 ​

   

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S. Amamah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

 begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator x squared minus 4 over denominator x squared plus 2 x plus 1 end fraction equals 0 end style   

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Pembahasan

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begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 2 of space fraction numerator x squared minus 4 over denominator x squared plus 2 x plus 1 end fraction end cell equals cell fraction numerator open parentheses 2 close parentheses squared minus 4 over denominator open parentheses 2 close parentheses squared plus 2 open parentheses 2 close parentheses plus 1 end fraction end cell row blank equals cell 0 over 9 end cell row blank equals 0 end table end style 

Jadi, begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator x squared minus 4 over denominator x squared plus 2 x plus 1 end fraction equals 0 end style   

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