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Pertanyaan

N i l ai d a r i x → 3 lim ​ ( x 3 + 2 x 2 − 15 x x 2 − 3 x ​ ) = ...

  1. 1 third

  2. 1 over 6

  3. 1 over 7

  4. 1 over 8

  5. 1 over 9

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A. Acfreelance

Master Teacher

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Pembahasan

D a l a m space m e n e n t u k a n space n i l a i space limit as x rightwards arrow a of fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fraction space y a n g space m e n g h a s i l k a n space b e n t u k space t a k space t e n t u space open parentheses 0 over 0 close parentheses space d a p a t space d i g u n a k a n space r u m u s colon  limit as x rightwards arrow a of fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fraction equals limit as x rightwards arrow a of fraction numerator f apostrophe left parenthesis x right parenthesis over denominator g apostrophe left parenthesis x right parenthesis end fraction  D e n g a n space f apostrophe left parenthesis x right parenthesis equals t u r u n a n space p e r t a m a space f left parenthesis x right parenthesis space d a n space g apostrophe left parenthesis x right parenthesis equals t u r u n a n space p e r t a m a space g left parenthesis x right parenthesis  equals fraction numerator 2.3 minus 3 over denominator 3 left parenthesis 3 right parenthesis squared plus 4.3 minus 15 end fraction  equals fraction numerator 6 minus 3 over denominator 27 plus 12 minus 15 end fraction  equals 3 over 24  equals 1 over 8

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N i l ai d a r i x → 2 lim ​ x 2 − 2 x x 2 − x − 2 ​ a d a l ah ...

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