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Pertanyaan

N i l ai d a r i x → 3 lim ​ 4 − 5 x + 1 ​ x 2 − x − 6 ​ = ...

  1. -8

  2. -6

  3. 6

  4. 8

  5. infinity

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A. Acfreelance

Master Teacher

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Pembahasan

limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 over denominator 4 minus square root of 5 x plus 1 end root end fraction  equals limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 over denominator 4 minus square root of 5 x plus 1 end root end fraction cross times fraction numerator 4 plus square root of 5 x plus 1 end root over denominator 4 plus square root of 5 x plus 1 end root end fraction  equals limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator 16 minus left parenthesis 5 x plus 1 right parenthesis end fraction  equals limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator 15 minus 5 x end fraction  equals limit as x rightwards arrow 3 of fraction numerator left parenthesis x minus 3 right parenthesis left parenthesis x plus 2 right parenthesis left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator negative 5 left parenthesis x minus 3 right parenthesis end fraction  equals limit as x rightwards arrow 3 of fraction numerator left parenthesis x plus 2 right parenthesis left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator negative 5 end fraction  equals fraction numerator left parenthesis 3 plus 2 right parenthesis left parenthesis 4 plus square root of 5 left parenthesis 3 right parenthesis plus 1 end root right parenthesis over denominator negative 5 end fraction  equals fraction numerator 5 left parenthesis 8 right parenthesis over denominator negative 5 end fraction  equals 8

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Abet Nessa Sihombing

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Aria Wiraputra

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N i l ai d a r i x → 0 lim ​ x ​ − 7 ​ x − 7 ​ = .....

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