Pertanyaan

N i l ai d a r i x → 3 lim 4 − 5 x + 1 x 2 − x − 6 = ...

$N i l ai d a r i x \to 3 lim \frac{x ^{2} - x - 6}{4 - 5 x + 1} = ...$

-8
-6
6
8

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Jawaban terverifikasi

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$limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 over denominator 4 minus square root of 5 x plus 1 end root end fraction equals limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 over denominator 4 minus square root of 5 x plus 1 end root end fraction cross times fraction numerator 4 plus square root of 5 x plus 1 end root over denominator 4 plus square root of 5 x plus 1 end root end fraction equals limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator 16 minus left parenthesis 5 x plus 1 right parenthesis end fraction equals limit as x rightwards arrow 3 of fraction numerator x squared minus x minus 6 left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator 15 minus 5 x end fraction equals limit as x rightwards arrow 3 of fraction numerator left parenthesis x minus 3 right parenthesis left parenthesis x plus 2 right parenthesis left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator negative 5 left parenthesis x minus 3 right parenthesis end fraction equals limit as x rightwards arrow 3 of fraction numerator left parenthesis x plus 2 right parenthesis left parenthesis 4 plus square root of 5 x plus 1 end root right parenthesis over denominator negative 5 end fraction equals fraction numerator left parenthesis 3 plus 2 right parenthesis left parenthesis 4 plus square root of 5 left parenthesis 3 right parenthesis plus 1 end root right parenthesis over denominator negative 5 end fraction equals fraction numerator 5 left parenthesis 8 right parenthesis over denominator negative 5 end fraction equals 8$