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N i l ai d a r i x → 0 lim ​ ( 5 x 2 tan 2 x tan 3 x ​ ) = ...

  1. 1

  2. 1 fifth

  3. 2 over 5

  4. 3 over 5

  5. 6 over 5

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A. Acfreelance

Master Teacher

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Pembahasan

limit as x rightwards arrow 0 of open parentheses fraction numerator tan space 2 x space tan space 3 x over denominator 5 x squared end fraction close parentheses equals limit as x rightwards arrow 0 of open parentheses fraction numerator tan space 2 x space tan space 3 x over denominator 5 x squared end fraction close parentheses cross times 2 over 2 cross times 3 over 3  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals limit as x rightwards arrow 0 of fraction numerator tan 2 x over denominator 2 x end fraction limit as x rightwards arrow 0 of fraction numerator tan 3 x over denominator 3 x end fraction limit as x rightwards arrow 0 of 6 over 5  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals left parenthesis 1 right parenthesis left parenthesis 1 right parenthesis open parentheses 6 over 5 close parentheses  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals open parentheses 6 over 5 close parentheses

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Geco Gechoo

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Tentukanlah h → 0 lim ​ h tan ( x + h ) − tan x ​

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