Pertanyaan

D ik e t ah u i ( f o g ) ( x ) = x + 1 d an f ( x − 2 ) = ( x − 2 ) ( x − 1 ) . M aka ni l ai d a r i g − ( 2 ) [ d iba c a : g in v ers 2 ] a d a l ah ...

$D ik e t ah u i (f o g) (x) = x + 1 d an f (x - 2) = \frac{( x - 1 )}{( x - 2 )} . M aka ni l ai d a r i g - (2) [d iba c a : g in v ers 2] a d a l ah ...$

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Klaim

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

$f left parenthesis x minus 2 right parenthesis equals fraction numerator left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 2 right parenthesis end fraction I n v e r s rightwards arrow x minus 2 space a g a r space d i t e m u k a n space n i l a i space d a r i space f left parenthesis x right parenthesis y equals x minus 2 x equals y plus 2 left right arrow y equals x plus 2 space m a k a colon f left parenthesis x right parenthesis equals fraction numerator left square bracket left parenthesis x plus 2 right parenthesis minus 1 right square bracket over denominator left square bracket left parenthesis x plus 2 right parenthesis minus 2 right square bracket end fraction left parenthesis f o g right parenthesis left parenthesis x right parenthesis equals f left parenthesis g left parenthesis x right parenthesis right parenthesis f left parenthesis g left parenthesis x right parenthesis right parenthesis equals x plus 1 fraction numerator left square bracket g left parenthesis x right parenthesis plus 1 right square bracket over denominator g left parenthesis x right parenthesis end fraction equals x plus 1 g left parenthesis x right parenthesis plus 1 equals left parenthesis x plus 1 right parenthesis. g left parenthesis x right parenthesis g left parenthesis x right parenthesis plus 1 equals x. g left parenthesis x right parenthesis plus g left parenthesis x right parenthesis minus x. g left parenthesis x right parenthesis equals negative 1 g left parenthesis x right parenthesis equals 1 over x y equals 1 over x rightwards arrow x equals 1 over y g to the power of negative 1 end exponent left parenthesis x right parenthesis equals 1 over x J a d i comma space n i l a i space d a r i space g minus apostrophe left parenthesis 2 right parenthesis equals 1 half$