Pembahasan

Gunakan integral subtitusi Jadi,

Gunakan integral subtitusi

$u equals csc open parentheses 3 x minus pi over 4 close parentheses du over dx equals negative 3 csc open parentheses 3 straight x minus straight pi over 4 close parentheses cot open parentheses 3 straight x minus straight pi over 4 close parentheses dx equals fraction numerator du over denominator negative 3 csc open parentheses 3 straight x minus straight pi over 4 close parentheses cot open parentheses 3 straight x minus straight pi over 4 close parentheses end fraction$

Jadi,

$integral open parentheses 6 cot open parentheses 3 x minus pi over 4 close parentheses csc open parentheses 3 x minus pi over 4 close parentheses close parentheses d x equals integral open parentheses 6 cot open parentheses 3 x minus pi over 4 close parentheses csc open parentheses 3 x minus pi over 4 close parentheses close parentheses fraction numerator d u over denominator negative 3 csc open parentheses 3 x minus pi over 4 close parentheses cot open parentheses 3 x minus pi over 4 close parentheses end fraction equals integral left parenthesis negative 2 right parenthesis d u equals negative 2 u plus C equals negative 2 csc open parentheses 3 x minus pi over 4 close parentheses plus C$