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D u a bi l an g an b u l a t m d an n m e m e n u hi h u b u n g an 2 m + n = − 40. N i l ai minim u m d a r i p = m 2 + n 2 a d a l ah ...

  1. 405

  2. 395

  3. 320

  4. 260

  5. 200

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F. Pratama

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Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

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Pembahasan

2 m plus n equals negative 40 rightwards double arrow n equals negative 2 m minus 40 horizontal ellipsis.. left parenthesis 1 right parenthesis  p equals m squared plus n squared    S u b t i t u s i k a n space p e r s a m a a n space left parenthesis 1 right parenthesis space colon  p equals m squared plus left parenthesis negative 2 m minus 40 right parenthesis squared  p equals m squared plus 4 m squared plus 160 m plus 1600  p equals 5 m squared plus 160 m plus 1600    U n t u k space m e n c a r i space n i l a i space m i n i m u m space m a k a space p to the power of apostrophe equals 0  10 m plus 160 equals 0 space  m equals negative 16 space    S u b t i t u s i space k e space p e r s a m a a n space left parenthesis 1 right parenthesis space colon  n equals negative 2 left parenthesis negative 16 right parenthesis minus 40 equals negative 8    M a k a  p subscript m i n end subscript equals left parenthesis negative 16 right parenthesis squared plus left parenthesis negative 8 right parenthesis squared equals 320

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Dua bilangan bulat m dan n memenuhi hubungan 2 m − n = 40 . Nilai minimum dari p = m 2 + n 2 adalah....

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