Iklan

Iklan

Pertanyaan

 

Error converting from MathML to accessible text.

Error converting from MathML to accessible text.

  1. 2 comma 25 space cross times space 10 space to the power of 6 N. C to the power of negative 1 end exponent

  2. 2 comma 45 cross times 10 to the power of 6 N. C to the power of negative 1 end exponent

  3. 5 comma 25 space cross times 10 to the power of 6 N. C to the power of negative 1 end exponent

  4. 6 comma 75 cross times 10 to the power of 6 N. C to the power of negative 1 end exponent

  5. 9 comma 00 space cross times space 10 to the power of 6 N. C to the power of negative 1 end exponent

Iklan

Y. Maghfirah

Master Teacher

Jawaban terverifikasi

Iklan

Pembahasan

Kuat space medan space listrik space muatan space 1 space yang space dirasakan space oleh space titik space straight P space adalah colon  straight E subscript 1 equals straight k fraction numerator straight q subscript 1 over denominator straight R subscript 1 superscript 2 end fraction equals left parenthesis 9 space straight x space 10 to the power of 9 right parenthesis space fraction numerator left parenthesis 40 space straight x space 10 to the power of negative 6 end exponent right parenthesis over denominator left parenthesis 40 space straight x space 10 to the power of negative 2 end exponent right parenthesis squared end fraction equals 2 comma 25 space straight x space 10 to the power of 6 space straight N divided by straight C

Kuat space medan space listrik space muatan space 2 space yang space dirasakan space oleh space titik space straight C space adalah colon  straight E subscript 2 equals straight k fraction numerator straight q subscript 2 over denominator straight R subscript 2 superscript 2 end fraction equals left parenthesis 9 space straight x space 10 to the power of 9 right parenthesis space fraction numerator left parenthesis 5 space straight x space 10 to the power of negative 6 end exponent right parenthesis over denominator left parenthesis 10 space straight x space 10 to the power of negative 2 end exponent right parenthesis squared end fraction equals 4 comma 5 space straight x space 10 to the power of 6 space straight N divided by straight C  Maka comma space kuat space medan space listrik space total space yang space dirasakan space oleh space titik space straight C space adalah

straight E subscript straight c equals straight E subscript 2 minus straight E subscript 1  straight E subscript straight c space equals left parenthesis 4 comma 5 space minus space 2 comma 25 right parenthesis space straight x space 10 to the power of 6  straight E subscript straight c space equals space 2 comma 25 space straight x space 10 to the power of 6 space end exponent straight N divided by straight C

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4

The Guy

Jawaban tidak sesuai

Iklan

Iklan

Pertanyaan serupa

Dua buah muatan listrik A = 4 q dan B = q terpisah sejauh 1 dm. Dimana letak titik yang kuat medan listriknya noljika muatan A positif dan B positif?

2

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia