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x→0lim​x2cosmx−cosnx​=...

Pertanyaan

limit as x rightwards arrow 0 of fraction numerator cos space m x minus cos space n x over denominator x squared end fraction equals...    

  1.  1 half left parenthesis n squared minus m squared right parenthesis 

  2.  1 half left parenthesis m squared minus n squared right parenthesis  

  3. n squared minus m squared  

  4.  m squared minus n squared   

  5. infinity   

Pembahasan Video:

Pembahasan Soal:

Ingat kembali selisih cosinus, sifat limit dan limit fungsi trigonometri berikut.

  • cos space A minus cos space B equals negative 2 space sin space left parenthesis fraction numerator A plus B over denominator 2 end fraction right parenthesis space sin space left parenthesis fraction numerator A minus B over denominator 2 end fraction right parenthesis 

 

  • limit as x rightwards arrow c of f left parenthesis x right parenthesis times g left parenthesis x right parenthesis equals limit as x rightwards arrow c of space f left parenthesis x right parenthesis times limit as x rightwards arrow c of space g left parenthesis x right parenthesis 

 

  • limit as x rightwards arrow c of k space f left parenthesis x right parenthesis equals k limit as x rightwards arrow c of f left parenthesis x right parenthesis

 

  • limit as x rightwards arrow 0 of fraction numerator sin space a x over denominator b x end fraction equals limit as x rightwards arrow 0 of fraction numerator space a x over denominator sin space b x end fraction equals a over b

​​​​​​​

  • left parenthesis a plus b right parenthesis left parenthesis a minus b right parenthesis equals a squared minus b squared 

Dari aturan di atas, maka diperoleh

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 0 of fraction numerator cos space m x minus cos space n x over denominator x squared end fraction end cell equals cell limit as x rightwards arrow 0 of space fraction numerator negative 2 space sin space left parenthesis begin display style fraction numerator m x plus n x over denominator 2 end fraction end style right parenthesis space sin space left parenthesis begin display style fraction numerator m x minus n x over denominator 2 end fraction end style right parenthesis over denominator x squared end fraction end cell row blank equals cell limit as x rightwards arrow 0 of space fraction numerator negative 2 space sin space left parenthesis begin display style fraction numerator m plus n over denominator 2 end fraction end style right parenthesis x space times space sin space left parenthesis begin display style fraction numerator m minus n over denominator 2 end fraction end style right parenthesis x over denominator x times x end fraction end cell row blank equals cell negative 2 space limit as x rightwards arrow 0 of space fraction numerator sin space left parenthesis fraction numerator m plus n over denominator 2 end fraction right parenthesis x over denominator x end fraction times limit as x rightwards arrow 0 of space fraction numerator sin space left parenthesis fraction numerator m minus n over denominator 2 end fraction right parenthesis x over denominator x end fraction end cell row blank equals cell negative 2 times left parenthesis fraction numerator m plus n over denominator 2 end fraction right parenthesis times left parenthesis fraction numerator m minus n over denominator 2 end fraction right parenthesis end cell row blank equals cell negative 1 half left parenthesis m plus n right parenthesis left parenthesis m minus n right parenthesis end cell row blank equals cell negative 1 half left parenthesis m squared minus n squared right parenthesis end cell row blank equals cell 1 half left parenthesis negative m squared plus n squared right parenthesis end cell row blank equals cell 1 half left parenthesis n squared minus m squared right parenthesis end cell end table end style       

Dengan demikian, limit as x rightwards arrow 0 of fraction numerator cos space m x minus cos space n x over denominator x squared end fraction equals 1 half left parenthesis n squared minus m squared right parenthesis.

Jadi, jawaban yang benar adalah A.

 

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

N. Puspita

Terakhir diupdate 07 Oktober 2021

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